在使用Jquery打开窗口之前检查弹出窗口是否已打开

时间:2012-06-04 13:23:40

标签: javascript jquery html

我想在打开弹出窗口之前检查弹出窗口是否已打开。 如何使用Jquery完成它?

以下是我打开新弹出窗口的代码:

window.open("mystopchat.php?stat=1&session="+data['myid1']['session_id'][i],"win1","width=500,height=500"); 

在我调用之前,我想确保此弹出窗口尚未打开。

5 个答案:

答案 0 :(得分:8)

这是我使用的一个小技巧,也许你可以使用它:

    var winRef; //This holds the reference to your page, to see later it is open or not

    function openWindow() {  
        var url = //Your URL;
        if (typeof (winRef) == 'undefined' || winRef.closed) {
            //create new, since none is open
            winRef = window.open(url, "_blank");
        }
        else {
            try {
                winRef.document; //if this throws an exception then we have no access to the child window - probably domain change so we open a new window
            }
            catch (e) {
                winRef = window.open(url, "_blank");
            }

            //IE doesn't allow focus, so I close it and open a new one
            if (navigator.appName == 'Microsoft Internet Explorer') {
                winRef.close();
                winRef = window.open(url, "_blank");
            }
            else {
                //give it focus for a better user experience
                winRef.focus();
            }
        }
    }

希望它有所帮助。

答案 1 :(得分:5)

var popup;
function openPopupOneAtATime() {
    if (popup && !popup.closed) {
       popup.focus();
       /* or do something else, e.g. close the popup or alert a warning */
    }
    else {
       popup = window.open(...);      
    }
}

答案 2 :(得分:0)

var newWindow = null;

function openwindow()
{
  // open the new window only if newWindow is null (not opened yet)
  // or if it was closed
  if ((newWindow == null) || (newWindow.closed))
    newWindow = window.open(...);
}

答案 3 :(得分:0)

试试这个(你会知道是否调用了打开的窗口):

var isOpen = "false";
function OpenPopup()
{
   if(isOpen == "false")
   {
         isOpen = "true"; 
         window.open("mystopchat.php?stat=1&session="+data['myid1']['session_id']  [i],"win1","width=500,height=500");
    }
} 

答案 4 :(得分:0)

这是我的建议:

function authorize(callback) {

if(!document.authorize) {
    console.log('Opening authorization window...');
    document.authorize = window.open('popup.html','tw','width=300,height=200');
}

if(document.authorize.closed) {
    console.log('Authorization window was closed...');
    setTimeout(callback,0); 
} else {
    setTimeout(function(){
        console.log('Authorization window still open...');
        authorize(callback);
    },1000);    
}

return false;
}


function test() {
    authorize(function(){
      alert('teste');
    });
}