Question

我正在尝试在jython中编写一个函数，它将组合来自两个不同列表的元素以创建一个单词。

例如：

该函数采用两个列表，两个名称分别为a和b

如果a是["eat", "pray", "love"] 而b是["er", "ing", "d"] 然后输入makeWord（a，b）它将返回：

["eater", "praying", "loved"]

到目前为止，我有：

def makeWords(a,b):
     a = []
    list1 = a
    b = []
    list2 = b
    new_list = []
    for word in list1:
        new_list.append((list1[i] + list2[i]))
    return new_list

但我知道我显然至少做了一些错事。任何帮助将非常感谢!!

Answer 1

怎么样：

map(lambda x: ''.join(x), zip(list1, list2))

或者说可读性更高：

map(''.join, zip(list1, list2))

Answer 2

这也应该有效：

>>> a = ["eat", "pray", "love"]
>>> b = ["er", "ing", "d"]
>>> [start + end for start, end in zip(a, b)]
['eater', 'praying', 'loved']

对于Joel Cornett，timeit代码：

import timeit

a = '''
a = ["eat", "pray", "love"]
b = ["er", "ing", "d"]
[start + end for start, end in zip(a, b)]
'''

b = '''
a = ["eat", "pray", "love"]
b = ["er", "ing", "d"]
map(lambda x: ''.join(x), zip(a, b))
'''

c = '''
a = ["eat", "pray", "love"]
b = ["er", "ing", "d"]
map(''.join, zip(a, b))
'''

timeit.Timer(a).timeit(number=1000000)
timeit.Timer(b).timeit(number=1000000)
timeit.Timer(c).timeit(number=1000000)

在jython中组合两个列表

2 个答案: