Question

我有2张桌子..一张客户桌......订单表......我试图从每个客户那里得到最后6个订单，但是对于所有的客户......我很难想到如何这样做哈哈..周五......任何帮助/想法？ ..我正在使用microsoft sql server studio，如果你需要知道

这是我现在的代码

select /*top 6*/ c.Company_name, oh.qms_control_nbr, c.reminder_notice 
from orderheader oh inner join clients c on oh.prnt_id = c.id
where c.status = 'Active'
group by c.company_name, oh.date_ordered, oh.qms_control_nbr, c.reminder_notice
order by c.company_name asc, c.reminder_notice asc, oh.Date_ordered desc

这给了我每个客户的所有订单，..只想限制到最后6个

所以......可能会给出这样的结果

_company_____              __order-num___
company a                     1111
company a                     1112
company a                     1113
company a                     1114
company a                     1115
company a                     1116
company b                     1221
company b                     1222
company b                     1433
company b                     1524
company b                     1345
company b                     1436

Answer 1

您可以使用ROW_NUMBER OLAP函数来获取此信息：

根据相关新信息进行修改。我认为这应该可以满足您的需求：

SELECT c.Company_name, oh.qms_control_nbr, c.reminder_notice 
FROM (SELECT t.*,
             ROW_NUMBER() OVER (PARTITION BY prnt_id ORDER BY date_ordered DESC) AS RN
      FROM orderheader t) oh
JOIN clients c
  ON oh.prnt_id = c.id
WHERE c.status = 'Active'
  AND oh.rn < 7
ORDER BY c.company_name asc, c.reminder_notice asc, oh.Date_ordered desc

Answer 2

select top 6 o.* from clienttable c
inner join orderstable o on c.columname = o.columnname
order by o.OrderProcessDate desc

将columnname和OrderProcessDate替换为正确的列。

获得所有公司的最后6个订单

2 个答案: