如何使用java中的telnet通过HTTP Request发送xml

时间:2012-06-21 04:58:02

标签: java httprequest telnet serversocket

我正在尝试通过Java中的telnet发送HTML POST请求,我有一些我必须发送的XML内容。但是当我尝试在java中实现时,我收到“连接重置”错误。但是当我在putty(unix)上做的时候,我正确地得到了响应xml。

我使用的Java程序:(导致连接重置错误)

public class Telnet {public static void main(String[] args) throws Exception {

       Socket socket = new Socket("hostname", 10020);
       String xmled = "<?xml version=1.0?><methodCall><methodName>GetVoucherDetails</methodName><params><param><value><struct><member><name>serialNumber</name><value><string>1038291567</string></value></member><member><name>networkOperatorId</name><value><string>vno2</string></value></member></struct></value></param></params></methodCall>"; 
       System.out.println("Params: " + xmled);

        try {
            Writer out = new OutputStreamWriter(socket.getOutputStream(), "UTF-8");
            out.write("POST /someContext HTTP/1.1\r\n");
            out.write("Accept: text/xml\r\n"); 
            out.write("Connection: close\r\n"); 
            out.write("Content-Length: 489\r\n"); 
            out.write("Content-Type: text/xml\r\n"); 
            out.write("Host: ws2258:10010\r\n"); 
            out.write("User-Agent: ADM/2.4/6.2\r\n"); 
            out.write("Authorization: Basic cHBtc3VzZXI6dnNfJF9wcG11NWVy\r\n");
            out.write(xmled);  
            out.write("\r\n");  
            out.flush();

            InputStream inputstream = socket.getInputStream();
            InputStreamReader inputstreamreader = new InputStreamReader(inputstream);
            BufferedReader bufferedreader = new BufferedReader(inputstreamreader);

            String string = null;
            string = bufferedreader.readLine();
            System.out.println(string);
            while ((string = bufferedreader.readLine()) != null) {
               System.out.println("Received " + string);
            }

       } catch(Exception e) {
           e.printStackTrace();
       } finally {
         socket.close(); 
       }
 }

}

请给我一些建议,我是套接字编程的新手。

2 个答案:

答案 0 :(得分:0)

在你的Socket构造函数中,你的意思是把端口10020?除非您的Web服务器正在侦听端口10020,否则HTTP意味着端口80。

答案 1 :(得分:0)

我终于找到了解决这个问题的方法。最后修复很简单。我们必须在一行中发送整个XML内容,而不是分成多行。

相关问题