Question

我有一个函数disp，我传递一个表的列名值来检查数据库中该列值是1还是0。如果值为1则应返回1否则为0这是我试图制作的函数。但没有给出理想的结果。

请告诉我是否有其他方法来检查特定行的列的值是1还是0

 function disp($x){
   @$ncenter=$_SESSION['ncenter'];
  $sql = "SELECT COUNT('$x') FROM sel WHERE 'numcenter' = '$ncenter' and '$x' = 1";
  $sql.=';';
   echo $sql;
 $res = mysql_query($sql);
  if(!$res) die ('Unable to run query:'.mysql_error());
  $row = mysql_fetch_array($res);
  if($row["COUNT('$x')"] > 0){

            return 0;
        }
      else{

            return 1; 
        }
 }

提前谢谢

Answer 1

// SELECT * FROM sel WHERE 'numcenter' = '$ncenter' and '$x' = 1 LIMIT 1

if(empty($row)){
    return 0;
}
else{
    return 1; 
}

Answer 2

您可以使用SQL CASE语句：

SELECT (CASE WHEN `column_name` = '1' THEN 1 ELSE 0 END) AS `column_name_equals_one` FROM `table_name` WHERE `row_identifier_column_name` = 'row_identifier_value';

编辑：我也重写了你的代码，因为它伤害了我的眼睛（我没有测试过这个）。

/**
 * Checks if the value of a specific field equals 1 or 0
 * 
 * @param string $columnName The name of the column
 * @param string $rowIdentifier The row identifier
 * @returns boolean|integer Returns false on failure or the query result as an integer on success
 */
function disp($columnName, $rowIdentifier) {
    $returnValue = false;

    $query = sprintf("SELECT (CASE WHEN `%s` = '1' THEN 1 ELSE 0 END) AS `result` FROM `table_name` WHERE `row_identifier_column_name` = '%s'", mysql_real_escape_string($columnName), mysql_real_escape_string($rowIdentifier));

    if (($result = mysql_query($query)) !== false) {
        if (($row = mysql_fetch_assoc($result)) !== false) {
            $returnValue = (int)$row['result']
        }

        mysql_free_result($result);
    }

    return $returnValue;
}

Answer 3

试试这个;

$row = mysql_result($res, 0, 0); 
$numb_of_rows = mysql_num_rows($row);
  if($numb_of_rows > 0){ 

            return 1; 
        } 
      else{ 

            return 0;  
        }

检查列值，如果1返回1，则返回0

3 个答案: