我有一个很长的脚本,我希望能够在需要时运行整个文件,而不用担心它的部分内容是否已经运行。但是下面的脚本给了我一些问题。由于某种原因,即使列'EntityID'和'EntityType'不存在,它也会越过IF语句,在这种情况下它不应该通过IF语句。谁能告诉我有什么问题?
IF EXISTS (SELECT * FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_NAME = 'Notes' AND COLUMN_NAME IN ('EntityId', 'EntityType'))
BEGIN
BEGIN TRANSACTION
--Delete notes where EntityType and EntityID are both NULL
DELETE FROM [dbo].[Notes]
WHERE [EntityId] = NULL
AND [EntityType] = NULL
--Delete notes where the corresponding contact or account has been deleted.
OR [ID] IN (9788, 10684, 10393, 10718, 10719)
--Populate new columns with all existing data
UPDATE [dbo].[Notes]
SET [AccountId] = [EntityId]
WHERE [EntityType] = 1
UPDATE [dbo].[Notes]
SET [ContactId] = [EntityId]
WHERE [EntityType] = 2
--Delete EntityId and EntityType columns from the Notes table
ALTER TABLE [dbo].[Notes]
DROP COLUMN [EntityId], [EntityType]
COMMIT
END
GO
表格的脚本
CREATE TABLE [dbo].[Notes](
[ID] [int] IDENTITY(1,1) NOT NULL,
[AnnotationID] [uniqueidentifier] NULL,
[CreatedBy] [int] NULL,
[CreatedDate] [datetime] NULL,
[NoteText] [ntext] NULL,
[OriginalAnnotationID] [uniqueidentifier] NULL,
[Active] [bit] NULL,
[ContactId] [int] NULL,
[AccountId] [int] NULL,
CONSTRAINT [PK_Notes] PRIMARY KEY CLUSTERED
(
[ID] ASC
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY] TEXTIMAGE_ON [PRIMARY]
GO
ALTER TABLE [dbo].[Notes] WITH CHECK ADD CONSTRAINT [FK_Account_ID] FOREIGN KEY([AccountId])
REFERENCES [dbo].[Account] ([ID])
GO
ALTER TABLE [dbo].[Notes] CHECK CONSTRAINT [FK_Account_ID]
GO
ALTER TABLE [dbo].[Notes] WITH CHECK ADD CONSTRAINT [FK_ContactId_ID] FOREIGN KEY([ContactId])
REFERENCES [dbo].[Contact] ([ID])
GO
ALTER TABLE [dbo].[Notes] CHECK CONSTRAINT [FK_ContactId_ID]
GO
错误:
Msg 207, Level 16, State 1, Line 6
Invalid column name 'EntityId'.
Msg 207, Level 16, State 1, Line 7
Invalid column name 'EntityType'.
Msg 207, Level 16, State 1, Line 12
Invalid column name 'EntityType'.
Msg 207, Level 16, State 1, Line 16
Invalid column name 'EntityType'.
答案 0 :(得分:4)
IF
内的内容并忽略您的IF
是否会平移。这与你不能做的原因相同:
IF 1 = 1
CREATE TABLE #x(a INT);
ELSE
CREATE TABLE #x(b INT);
一种解决方法是使用动态SQL:
IF EXISTS ...
BEGIN
BEGIN TRANSACTION;
DECLARE @sql NVARCHAR(MAX);
SET @sql = N'
DELETE FROM [dbo].[Notes]
WHERE [EntityId] IS NULL
AND [EntityType] IS NULL
--Delete notes where the corresponding contact or account has been deleted.
OR [ID] IN (9788, 10684, 10393, 10718, 10719)
--Populate new columns with all existing data
UPDATE [dbo].[Notes]
SET [AccountId] = [EntityId]
WHERE [EntityType] = 1
UPDATE [dbo].[Notes]
SET [ContactId] = [EntityId]
WHERE [EntityType] = 2
--Delete EntityId and EntityType columns from the Notes table
ALTER TABLE [dbo].[Notes]
DROP COLUMN [EntityId], [EntityType]';
EXEC sp_executesql @sql;
COMMIT TRANSACTION;
END
但你仍然应该确定两个列都在那里。
答案 1 :(得分:0)
我怀疑问题是其中一个列存在但不是两个。请尝试以下方法:
IF 2 = (SELECT count(*) FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_NAME = 'Notes' AND COLUMN_NAME IN ('EntityId', 'EntityType'))