Question

我有以下xquery表达式，用于从XML数据库返回特定CD的标题

String queryString =
                "declare variable $docName as xs:string external;"  + sep +    
                "for $cd in doc($docName)/*/"+"CD[1]"+"/TITLE"+        
                " return $cd/text()";
     XQPreparedExpression expr = conn.prepareExpression(queryString);
     expr.bindString(new QName("docName"), filename,
              conn.createAtomicType(XQItemType.XQBASETYPE_STRING));
     XQResultSequence rs = expr.executeQuery();
     while(rs.next()){
         System.out.println(rs.getObject());
     }

我从此查询中获得的输出具有以下格式

[#text: 1999 Grammy Nominees]

问题是，如何改进查询以使输出摆脱“#text：”的东西，并且只产生-1999格莱美提名 - 。感谢。

Answer 1

确实

String queryString =
                "declare variable $docName as xs:string external;"  + sep +    
                "for $cd in doc($docName)/*/"+"CD[1]"+"/TITLE"+        
                " return string($cd)";

XQResultSequence rs = expr.executeQuery();
     while(rs.next()){
         System.out.println(rs.getAtomicValue());
     }

做你想做的事吗？

从xml元素标记中提取值

1 个答案: