Question

我有一个byte []数组，偶数个长度。现在，我希望byte []数组突破其长度的一半，byte []数组中的前两个字节为字节b1，接下来两个为字节b2，依此类推。

请帮忙。感谢

Answer 1

这是家庭作业吗？我想你的主要问题是将字节对组合成双字节。这是通过所谓的左移（<<）来实现的，字节是8位，因此移位8：

int doubleByte = b1 + (b2 << 8);

注意，我使用b1作为低位字节，b2作为高位字节。

其余的很简单：分配一个int数组，其长度是字节数组的一半，然后遍历字节数组以构建新的int数组。希望这会有所帮助。

Answer 2

也许我完全理解你的问题。

public class Main {
    // run this
    public static void main(String[] args) {    

        // create the array and split it
        Main.splitArray(new byte[10]);
    }

    // split the array
    public static void splitArray(byte[] byteArray) {
        int halfSize = 0; // holds the half of the length of the array
        int length = byteArray.length; // get the length of the array
        byte[] b1 = new byte[length / 2]; // first half
        byte[] b2 = new byte[length / 2]; // second half
        int index = 0;

        if (length % 2 == 0) { // check if the array length is even
            halfSize = length / 2; // get the half length

            while (index < halfSize) { // copy first half
                System.out.println("Copy index " + index + " into b1's index " + index);
                b1[index] = byteArray[index];
                index++;
            }

            int i = 0; // note the difference between "i" and "index" !
            while (index < length) { // copy second half
                System.out.println("Copy index " + index + " into b2's index " + i);// note the difference between "i" and "index" !
                b2[i] = byteArray[index];// note the difference between "i" and "index" !
                index++;
                i++; //dont forget to iterate this, too
            }

        } else {
            System.out.println("Length of array is not even.");
        }
    }
}

将byte []数组转换为byte数

2 个答案: