给出一个uri的java发送八位字节流

时间:2012-06-26 20:51:46

标签: c# java stream httpwebrequest

在c#中,我能够做到这一点:

        HttpWebRequest request = WebRequest.Create(address) as HttpWebRequest;
        request.Method = "POST";
        request.ContentType = "application/octet-stream";

        request.ContentLength = fileToSend.Length;
        request.Timeout = 2000000000;
        using (Stream requestStream = request.GetRequestStream())
        {
            // Send the file as body request.
            requestStream.Write(fileToSend, 0, fileToSend.Length);
            requestStream.Close();
        }

我正在寻找一个类似的对象,我可以在Java中使用它来扮演HttpWebRequest,它将包含一个Stream。

谢谢!

编辑:发现这个Using java.net.URLConnection to fire and handle HTTP requests但是看起来太复杂了......希望有一种更简单的方法吗?

1 个答案:

答案 0 :(得分:0)

我建议您查看Apache HTTP Client(http://hc.apache.org/httpclient-3.x/features.html)。

如果您只需要来自某个资源的查询信息,那么标准JDK就足够了:

java.net.URL url = new java.net.URL("http://foo.bar");
URLConnection conn = url.openConnection();
//conn.getOutputStream() to place information
//conn.getInputStream() to read resource
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