Question

有两个清单：

List<string> excluded = new List<string>() { ".pdf", ".jpg" };
List<string> dataset = new List<string>() {"valid string", "invalid string.pdf", "invalid string2.jpg","valid string 2.xml" };

如何从“数据集”列表中筛选出包含“已排除”列表中任何关键字的值？

Answer 1

var results = dataset.Where(i => !excluded.Any(e => i.Contains(e)));

Answer 2

尝试：

var result = from s in dataset
             from e in excluded 
             where !s.Contains(e)
             select e;

Answer 3

var result=dataset.Where(x=>!excluded.Exists(y=>x.Contains(y)));

当排除列表为空时，这也有效。

Answer 4

// Contains four values.
int[] values1 = { 1, 2, 3, 4 };

// Contains three values (1 and 2 also found in values1).
int[] values2 = { 1, 2, 5 };

// Remove all values2 from values1.
var result = values1.Except(values2);

https://www.dotnetperls.com/except

Answer 5

var结果=数据集。其中（x =>！excluded.Contains（x））;

排除包含其他列表中的值的列表项

5 个答案: