Question

我熟悉C.我可以写这样的地方：

uint array[0xFFFF][20];

但我不知道如何在Csharp中做到这一点。我尝试了所有的MS教程和其他教程，但没有运气。

有人可以帮帮我吗？

Answer 1

Official tutorial。基本上，您首先创建“外部”数组，然后循环它，并分别创建每个“内部”数组。

两个例子：

int[][] a = new int[] { new int[]{ 1, 2 }, new int[]{ 3, 4, 5, 6, 7 }};

int[][] c = new int[100][];
for (int i = 0; i < c.length; i++) c[i] = new int[5];

如果您只需要2D矩形阵列，则可以使用int[,] b = new int[10, 7];。

Answer 2

int[][] jaggedArray = new int[3][];
jaggedArray[0] = new int[5];
jaggedArray[1] = new int[4];
jaggedArray[2] = new int[2];

或

jaggedArray[0] = new int[] { 1, 3, 5, 7, 9 };
jaggedArray[1] = new int[] { 0, 2, 4, 6 };
jaggedArray[2] = new int[] { 11, 22 };

请参阅Jagged Arrays (C# Programming Guide)

Answer 3

我不知道在C中，但在c＃中你可以使用锯齿状数组，如：

// Declare local jagged array with 3 rows.
    int[][] jagged = new int[3][];

    // Create a new array in the jagged array, and assign it.
    jagged[0] = new int[2];
    jagged[0][0] = 1;
    jagged[0][1] = 2;

    // Set second row, initialized to zero.
    jagged[1] = new int[1];

    // Set third row, using array initializer.
    jagged[2] = new int[3] { 3, 4, 5 };

    // Print out all elements in the jagged array.
    for (int i = 0; i < jagged.Length; i++)
    {
        int[] innerArray = jagged[i];
        for (int a = 0; a < innerArray.Length; a++)
        {
        Console.Write(innerArray[a] + " ");
        }
        Console.WriteLine();
    }

http://www.dotnetperls.com/jagged-array

Answer 4

我认为这可能会对你有所帮助

       static void Main(string[] args)
    {
        Console.WriteLine("enter the size of rows");

        int n = Convert.ToInt32(Console.ReadLine());

        int[][] a = new int[n][];
        for (int i = 0; i < a.Length; i++)
        {
            Console.WriteLine("enter the number of elements for row {0}", i + 1);
            int x = Convert.ToInt32(Console.ReadLine());
            a[i]=new int[x];
            for (int j = 0; j < a[i].Length; j++)
            {
                a[i][j] = Convert.ToInt32(Console.ReadLine());
            }
        }
        for (int i = 0; i < a.Length; i++)
        {
            for (int j = 0; j < a[i].Length; j++)
            {
                Console.Write(a[i][j]+"\t"); 
            }
            Console.WriteLine();
        }

            Console.ReadKey();
    }

Answer 5

namespace jaggedarray
{
    class Program
    {
        static void Main(string[] args)
        {

            int[][] jagged = new int[5][];
            jagged[0] = new int[4] { 22, 33,44,55 };
            jagged[1] = new int[1] { 2 };
            jagged[2] = new int[4] { 1, 2, 3, 4 };
            jagged[3] = new int[2] { 12,13};
            jagged[4] = new int[1] {2};
            for (int i = 0; i < jagged.Length; i++ ) {
                for (int j = 0; j < jagged[i].Length; j++)
                {
                    Console.Write("\t{0}",jagged[i][j]);
                }
                Console.WriteLine();
                Console.WriteLine();
            }

            // input jagged array

            int [][] arrays=new int[5][];
            Console.WriteLine("Please Enter the ValueType to make a jagged array:");
            arrays[0] = new int[1];
            arrays[1] = new int[2];
            arrays[2]=new int [3];
            arrays[3]=new int [4];
            arrays[4] = new int[5];
            for (int i = 0; i < arrays.Length;i++ ) {

                for (int j = 0; j < arrays[i].Length; j++)
                {
                    arrays[i][j] = Convert.ToInt32(Console.ReadLine());
                }
            }

            Console.WriteLine("This is jagged array::");
            for (int i = 0; i < arrays.Length;i++ ) {

                for (int j = 0; j < arrays[i].Length;j++ ) {
                    Console.Write("\t{0}", arrays[i][j]);

                }
                Console.WriteLine();
            }
        }

    }
}

Answer 6

创建和显示锯齿状数组元素

 int[][] a = new int[2][];//its mean num of row is 2 which fixed
        int choice;//thats i left on user choice that how many number of column in each row he wanna to declare

        for (int row = 0; row < a.Length; row++)
        {
            Console.WriteLine("pls enter number of colo in row {0}", row);
            choice = int.Parse(Console.ReadLine());
            a[row] = new int[choice];
            for (int col = 0; col < a[row].Length; col++)
            {
                a[row][col] = int.Parse(Console.ReadLine());
            }
        }
        //loop for out put the values of jagged array
        for (int row = 0; row < a.Length; row++)
        {
            for (int col = 0; col < a[row].Length; col++)
                Console.Write(a[row][col]+"\t");
            Console.WriteLine("");
        }

这里插入循环使用

a [row] .length

而不是

则为a.length，

背后的原因是每一行都有不同的列数，所以在第二个循环中你必须提到每行的长度

如何在c＃中创建锯齿状数组？

6 个答案: