Question

我有一个很大的wav文件，我想进入较小的块。我还有一个.cue文件，它具有帧速率长度，较小的块应该是。我想出了如何分割wav，但所有的wav文件都是相同的声音。似乎每当我创建一个新的wav时，大的wav文件从头开始并使新波的长度正确但声音相同。

我想我需要一种方法来读取特定帧的wav，然后写入文件，然后继续读取并写入另一个文件等...

我已经在这几个小时了，似乎无法弄明白。任何帮助将不胜感激。这是我的代码，所有注释的东西都是我错误的代码，我一直在尝试。

 int count2 = 0;
  int totalFramesRead = 0;
        //cap contains the how many wav's are to be made
        //counter contains the vector position.
        String wavFile1 = "C:\\Users\\DC3\\Desktop\\wav&text\\testwav.wav";
            //String wavFile2 = "C:\\Users\\DC3\\Desktop\\waver\\Battlefield.wav";
            while(count2 != counter){
            try {
                    AudioInputStream clip1 = AudioSystem.getAudioInputStream(new File(wavFile1));
                    int bytesPerFrame = clip1.getFormat().getFrameSize();
                    //System.out.println(bytesPerFrame);
//                     int numBytes = safeLongToInt(clip1.getFrameLength()) * bytesPerFrame; 
//                     byte[] audioBytes = new byte[numBytes];
//                     int numBytesRead = 0;
//                     int numFramesRead = 0;
//                     // Try to read numBytes bytes from the file.
//                     while ((numBytesRead = 
//                       clip1.read(audioBytes)) != -1) {
//                       // Calculate the number of frames actually read.
//                       clip1.read(audioBytes)
//                       numFramesRead = numBytesRead / bytesPerFrame;
//                       totalFramesRead += numFramesRead;
//                       System.out.println(totalFramesRead);
//                     }

                    long lengthofclip = Integer.parseInt(time.get(count2))- silence;

                    globallength = clip1.getFrameLength();
                    AudioInputStream appendedFiles = new AudioInputStream(clip1, clip1.getFormat(), lengthofclip);
                    //long test = (appendedFiles.getFrameLength() *24 *2)/8;
                    //int aaaaa = safeLongToInt(test);
                    //appendedFiles.mark(aaaaa);
                    AudioSystem.write(appendedFiles, 
                            AudioFileFormat.Type.WAVE, 
                            new File("C:\\Users\\DC3\\Desktop\\wav&text\\" + name.get(count2)));
                            count2++;
            } catch (Exception e) {
                    e.printStackTrace();
            }
        }
  }
  public static int safeLongToInt(long l) {
    if (l < Integer.MIN_VALUE || l > Integer.MAX_VALUE) {
        throw new IllegalArgumentException
            (l + " cannot be cast to int without changing its value.");
    }
    return (int) l;
}

Answer 1

乍一看只是一个想法，但我假设这条线路出了问题：

AudioInputStream clip1 = AudioSystem.getAudioInputStream(new File(wavFile1));

把它放在你的while循环之外，这样就不会在每个循环中重新创建它。像这样：

//...
    String wavFile1 = "C:\\Users\\DC3\\Desktop\\wav&text\\testwav.wav";
    AudioInputStream clip1 = AudioSystem.getAudioInputStream(new File(wavFile1));
    int bytesPerFrame = clip1.getFormat().getFrameSize();

        while(count2 != counter){
        try {
//...

这也假设你的算法是正确的，我不会浪费时间思考，因为你没有问这个问题:-D

在Java中将Big Wav文件提取为较小的块

1 个答案: