Question

我很难用mysql查询。请帮我。这是我的查询，我得到了正确的结果，但我需要在mysql中修改结果。

                SELECT  bu.username,
                    bg.id as goal_id,
                    br.id as reason_id,
                    (SELECT COUNT(test_reason_id) FROM test_rank WHERE test_reason_id = br.id) as point
                FROM
                    test_goal AS bg INNER JOIN test_reason AS br ON 
                    br.user_id=bg.user_id INNER JOIN test_user AS bu ON
                    br.user_id=bu.id
                WHERE
                    bg.id       =   br.test_goal_id
                GROUP BY
                    bg.id
                ORDER BY
                    point DESC

于此项目表格-1 当我使用ORDER BY点DESC然后看起来像表-2

时，我的实际表格看起来像这样

username     goal_id    reason_id   point
 khan           8            3        2
 john           6            9        5
 yoyo           5           21        4
 smith         11            6        5

于此项目表格-2 我的结果集看起来像这样

username     goal_id    reason_id   point
 john           6            9        5
 smith         11            6        5
 yoyo           5           21        4
 khan           8            3        2

但我希望我的结果集像这样

username     goal_id    reason_id   point   rank
 john           6            9        5       1
 smith         11            6        5       2
 yoyo           5           21        4       3
 khan           8            3        2       4

这可能吗？请任何人帮助我。对我来说太难了。

Answer 1

添加如下行计数变量：

select a.*,  (@row := @row + 1) as rank
from (
      SELECT  bu.username,
                bg.id as goal_id,
                br.id as reason_id,
                (SELECT COUNT(test_reason_id) FROM test_rank WHERE test_reason_id = br.id) as point                   
            FROM
                test_goal AS bg INNER JOIN test_reason AS br ON 
                br.user_id=bg.user_id INNER JOIN test_user AS bu ON
                br.user_id=bu.id                    
            WHERE
                bg.id       =   br.test_goal_id
            GROUP BY
                bg.id
            ORDER BY
                point DESC
) a, (SELECT @row := 0) r

请参阅this simplified SQLFiddle example

如何根据mysql中的点添加排名

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