Question

我有一组看起来像这样的路线：

resources :placements do
  match '/foo' => "placements#foo"
  match '/bar' => "placements#bar"
end

这会产生与您期望的行为相符的路线：

/placements/1234/foo
/placements/1234/bar

但是，对于一些不需要单独放置的方法，我也需要“通用”路由。所以，我构建了一个如下所示的路由块：

resources :placements do
  match '/foo' => "placements#foo"
  match '/bar' => "placements#bar"
end
match '/placements/baz' => "placements#baz"

如果我rake routes，我会得到一条看起来不错的路线：

/placements/baz

注意缺少id。但是，如果我尝试访问该路由，Rails会尝试在控制器上调用show方法，就好像“baz”是ID，而不是方法名称。我如何构建一个路由结构，让我能够获得我所追求的内容，而不必将路由的第一段（placements）更改为其他内容？

Answer 1

将第二条路线移到resources区块上，即

match '/placements/baz' => "placements#baz"
resources :placements, :id => /\d+/ do
  match '/foo' => "placements#foo"
  match '/bar' => "placements#bar"
end

或为id中的resources添加正则表达式，例如：

resources :placements, :id => /\d+/ do
  match '/foo' => "placements#foo"
  match '/bar' => "placements#bar"
end
match '/placements/baz' => "placements#baz"

Rails 3：将“通用”控制器路由与标准资源路由混合

1 个答案: