带有join和group by的复杂选择查询

Question

我有两个mysql表，我想做一个选择查询：我的目标是为某个用户计算他从当前时间开始的最后七天的积分。 第一个表为每个订户呈现他从内容id 1 2或3打到特定内容的时间。 他可能在某一天没有内容点击，所以他今天不会得分。

表格显示在这些图片中。  我的选择查询不完整：

   SELECT SUM( points ) AS POINT, DAY FROM
 (SELECT content_hits.content_id, COUNT( * ) * points AS points, 
DATE_FORMAT( hit_time,  "%d-%m-%Y" ) AS  DAY 
FROM content_hits JOIN content 
WHERE content_hits.content_id = content.content_id AND subscriber_id =1
 AND DATE_FORMAT( hit_time,  "%Y-%m-%d" ) > ( CURDATE( ) - INTERVAL 7 DAY )
 GROUP BY content_hits.content_id, DAY) AS tm 
GROUP BY DAY 
ORDER BY DAY DESC

结果如下图所示：

我预计这几天的结果为零：17-7-2102 16-7-2012 15-7-2012 14-7-2012和12-7-2012。 有什么建议吗？

Answer 1

需要创建用于左连接的日历表

CREATE TABLE ints (i INTEGER);
INSERT INTO ints VALUES (0), (1), (2), (3), (4), (5), (6), (7), (8), (9);

将日历表连接到您的查询。

 SELECT cal.date,COALESCE(a.point,0) as point
 FROM (
    SELECT DATE_FORMAT(CURDATE() + INTERVAL a.i * 10 - b.i DAY,"%Y-%m-%d") as date
    FROM ints a JOIN ints b
    ORDER BY a.i * 10 - b.i
 ) cal LEFT JOIN 
 (SELECT SUM( points ) AS POINT, DAY FROM
  (SELECT content_hits.content_id, COUNT( * ) * points AS points, 
    DATE_FORMAT( hit_time,  "%Y-%m-%d" ) AS  DAY 
   FROM content_hits JOIN content 
   WHERE content_hits.content_id = content.content_id AND subscriber_id =1
     AND DATE_FORMAT( hit_time,  "%Y-%m-%d" ) > ( CURDATE( ) - INTERVAL 7 DAY )
   GROUP BY content_hits.content_id, DAY) AS tm 
   GROUP BY DAY 
 )a
 ON cal.date = a.day
 WHERE cal.date BETWEEN CURDATE( ) - INTERVAL 7 DAY AND CURDATE()
 ORDER BY cal.date desc;

SQL DEMO此处。