Question

好吧，所以我知道这是一个很大的程序，但我的问题很简单。我试图从中获取一个Bond的单个实例，但是由于我是管理员，它给了我每个实例的系统中与该代理相关的用户数。这发生在OR EXISTS语句的底部。我只需要帮助弄清楚如何将结果限制为每个债券的1，同时仍然得到所需金额的正确结果，这就是为什么个别的连接陈述是必要的。

ALTER PROCEDURE dbo.GetBondAmounts
    (
    @Username varchar(20)
    )
AS
    SELECT Bond.ID BondID, (ISNULL(Powers.Amount,0) + ISNULL(Charges.Amount,0)) BondAmount,
    (ISNULL(BondFee.Amount,0) + ISNULL(Powers.Premium,0) + ISNULL(Charges.Premium,0)
    + ISNULL(Forfeiture.CostOfApprehension,0) + ISNULL(Forfeiture.AmountPaid,0) + Bond.StateTax) BondTotal,
    (ISNULL(BondFee.Amount,0) + ISNULL(Powers.Premium,0) + ISNULL(Charges.Premium,0)
    + ISNULL(Forfeiture.CostOfApprehension,0) + ISNULL(Forfeiture.AmountPaid,0) + Bond.StateTax
    - ISNULL(BalanceForgiveness.Amount,0) - ISNULL(Payment.Amount,0)) BondBalance
    FROM Bond
    LEFT OUTER JOIN UserAgency ON Bond.Agency = UserAgency.Agency
    LEFT OUTER JOIN
    (
        SELECT BondID, SUM(AmountForgiven) Amount
        FROM BalanceForgiveness
        GROUP BY BondID
    ) AS BalanceForgiveness ON Bond.ID = BalanceForgiveness.BondID
    LEFT OUTER JOIN
    (
        SELECT Bond, SUM(Amount) Amount
        FROM BondFee
        GROUP BY Bond
    ) AS BondFee ON Bond.ID = BondFee.Bond
    LEFT OUTER JOIN
    (
        SELECT Powers.Bond, SUM(Charge.BondAmount) Amount,
        ISNULL(SUM(Charge.BondPremium), 0) Premium
        FROM Powers INNER JOIN Charge ON Powers.Surety = Charge.PowerSurety
        AND Powers.PowerPrefix = Charge.PowerPrefix AND Powers.PowerNumber = Charge.PowerNumber
        GROUP BY Bond
    ) AS Powers ON Bond.ID = Powers.Bond
    LEFT OUTER JOIN
    (
        SELECT BondID, SUM(BondAmount) Amount, SUM(BondPremium) Premium
        FROM ChargeWithoutPower
        GROUP BY BondID
    ) AS Charges ON Bond.ID = Charges.BondID
    LEFT OUTER JOIN
    (
        SELECT Bond, SUM(CostOfApprehension) CostOfApprehension, SUM(AmountPaid) AmountPaid
        FROM Forfeiture
        GROUP BY Bond
    ) AS Forfeiture ON Bond.ID = Forfeiture.Bond
    LEFT OUTER JOIN
    (
        SELECT Bond, SUM(Amount) Amount
        FROM Payment
        GROUP BY Bond
    ) AS Payment ON Bond.ID = Payment.Bond
    WHERE UserAgency.Username = @Username
    OR EXISTS (SELECT * FROM Users WHERE Username = @Username AND Admin = 1)

Answer 1

好的，所以我找到了自己的答案。我只需要使UserAgency与其他连接相同。以下是它的外观：

LEFT OUTER JOIN
(
    SELECT Agency, Username FROM UserAgency
    WHERE Username = @Username
) AS UserAgency ON Bond.Agency = UserAgency.Agency

使此功能返回不同的结果

1 个答案: