Question

我有一个像表单一样工作的应用程序，它需要四个字段并验证信息，以确保没有输入无效字符。这四个字段存储在变量中：

电话
名称
电子邮件

现在我想将表单数据（输入这四个字段并存储到变量中的任何内容）提交到url（将使用http://www.test.com），但我不知道如何执行此操作。我想我正在寻找一种叫做HttpURLConnection的东西，但我不知道如何指定发送哪个变量。我在网站http://developer.android.com/reference/java/net/HttpURLConnection.html

中找到了以下代码

private class UploadFilesTask extends AsyncTask<URL, Integer, Long>{
protected Long doInBackground(URL... urls) {

    try {
        HttpClient http = new DefaultHttpClient();
        HttpPost post = new HttpPost("http://www.test.com");

        List<NameValuePair> data = new ArrayList<NameValuePair>();
        data.add(new BasicNameValuePair("phone", "value"));
        data.add(new BasicNameValuePair("name", "value"));
        data.add(new BasicNameValuePair("email", "value"));
        data.add(new BasicNameValuePair("comments", "value"));
        post.setEntity(new UrlEncodedFormEntity(data));

        HttpResponse response = http.execute(post);
        // do something with the response
    }
    catch (ClientProtocolException e) {
        // do something
        finish();
    }
    catch (IOException e) {
        // do something
        finish();
    }

}

非常感谢任何帮助，谢谢！

Answer 1

将表单数据发送到服务器的最简单方法是使用HttpClient和HttpPost。

尝试这样的事情：

try {
    HttpClient http = new DefaultHttpClient();
    HttpPost   post = new HttpPost("http://www.example.com/process");

    List<NameValuePair> data = new ArrayList<NameValuePair>();
    data.add(new BasicNameValuePair("phone", "value");
    data.add(new BasicNameValuePair("name", "value");
    data.add(new BasicNameValuePair("email", "value");
    data.add(new BasicNameValuePair("comments", "value");
    post.setEntity(new UrlEncodedFormEntity(data));

    HttpResponse response = http.execute(post);
    // do something with the response
}
catch (ClientProtocolException e) {
    // do something
}
catch (IOException e) {
    // do something
}

注意，您需要在AsyncTask中执行此操作，这样您就不会锁定等待网络操作完成的UI线程。

修改

这是一个简单的快速示例，说明它在AsyncTask中的样子。

public class SendTask extends AsyncTask<Void, Void, Boolean> { String responseString; @Override protected Boolean doInBackground(Void... params) { try { HttpClient http = new DefaultHttpClient(); HttpPost post = new HttpPost("http://www.test.com"); List<NameValuePair> data = new ArrayList<NameValuePair>(); data.add(new BasicNameValuePair("phone", "value")); data.add(new BasicNameValuePair("name", "value")); data.add(new BasicNameValuePair("email", "value")); data.add(new BasicNameValuePair("comments", "value")); post.setEntity(new UrlEncodedFormEntity(data)); HttpResponse response = http.execute(post); responseString = new BasicResponseHandler(). handleResponse(response); // Basic handler return true; } catch (ClientProtocolException e) { // do something useful to recover from the exception // Note: there may not be anything useful to do here } catch (IOException e) { // do something useful to recover from the exception // Note: there may not be anything useful to do here } return false; } @Override protected void onPostExecute(Boolean success) { // TODO: Do something more useful here if (success) { Toast.makeText(MainActivity.this, "Success: " + responseString, Toast.LENGTH_LONG).show(); } else { Toast.makeText(MainActivity.this, "Failed", Toast.LENGTH_LONG).show(); } } }

Answer 2

将字段作为参数添加到网址。

String phone="phone=234432";
String name="name=John Smith";
String email="email=test@email.com"; 

Url = new URL("http://www.test.com?"+phone+"&"+name+"&"+email);

未经过测试，但它应该在GET Http请求中工作。

Answer 3

//使用xml请求

String url="http://www.test.com";
String xmlRequest="<message xmlns=\"http://test.com/schemas/ma\"><header></header>"+
"<body><phone>9944556622</phone><name>Mytest name</name><email>mytest@email.com</email>"+"<comments>hay this seems nice</comments></body></message>"

HttpPost httppost = new HttpPost(url);
    StringEntity se = new StringEntity(xmlRequest,HTTP.UTF_8);


httppost.setHeader("Content-Type","application/xml");
httppost.setHeader("Accept","application/xml");

httppost.setEntity(se);

BasicHttpResponse httpResponse = (BasicHttpResponse) httpclient.execute(httppost);

   StatusLine statusLine = httpResponse.getStatusLine();

Answer 4

    HttpClient httpClient = new DefaultHttpClient();
                    Log.i("sampath","line 139");
                    HttpPost httpPost = new HttpPost(url);

                    BasicNameValuePair usernameBasicNameValuePair = new BasicNameValuePair("textMessage", msg);

                    List<NameValuePair> nameValuePairList = new ArrayList<NameValuePair>();
                    nameValuePairList.add(usernameBasicNameValuePair);

                    try {

                        UrlEncodedFormEntity urlEncodedFormEntity = new UrlEncodedFormEntity(nameValuePairList);


                        httpPost.setEntity(urlEncodedFormEntity);

                        try {

                            HttpResponse httpResponse = httpClient.execute(httpPost);


                            InputStream inputStream = httpResponse.getEntity().getContent();

                            InputStreamReader inputStreamReader = new InputStreamReader(inputStream);

                            BufferedReader bufferedReader = new BufferedReader(inputStreamReader);

                            StringBuilder stringBuilder = new StringBuilder();

                            String bufferedStrChunk = null;

                            while((bufferedStrChunk = bufferedReader.readLine()) != null){
                                stringBuilder.append(bufferedStrChunk);
                            }

                            return stringBuilder.toString();

                        } catch (ClientProtocolException cpe) {
                            System.out.println("Firstption caz of HttpResponese :" + cpe);
                            cpe.printStackTrace();
                        } catch (IOException ioe) {
                            System.out.println("Secondption caz of HttpResponse :" + ioe);
                            ioe.printStackTrace();
                        }

                    } catch (UnsupportedEncodingException uee) {
                        System.out.println("Anption given because of UrlEncodedFormEntity argument :" + uee);
                        uee.printStackTrace();
                    }

//---------------------------------------------------------------------------
Here is the php file

<?php
$message = $_POST['textMessage'];
echo 'working fine'.$message;
$filename="androidmessages.html";
file_put_contents($filename,"Entered Text is:".$message."<br />",FILE_APPEND);
?>

如何将Android Activity中的变量提交到网站网址？

4 个答案: