我想序列化包含Date对象的Arraylist,然后能够对其进行反序列化并迭代反序列化版本。
目前我有一个名为DateSerialize的类,它实现了Serializable。我有一个方法可以将日期对象添加到arraylist中,然后一旦完成,我想序列化它。
下次当我运行程序时,我想反序列化该arraylist并以相同的顺序和格式获取这些对象,并希望在它上面运行迭代器。
任何人都可以帮我解决这个问题吗?
谢谢!
答案 0 :(得分:0)
如果你想使用Serializable,你应该没有问题,因为ArrayList是Serializable,就像String和每个基本类型一样。 public class DateSerialize implements Serializable {}
应该做其余的事情。您可以阅读有关此方法的更多信息here。但是,序列化还有很多其他选项。所以请更具体。
ArrayList aList = new ArrayList();
MyBusinessObject obj = new MyBusinessObject();
obj.Name = "MyName";
obj.Address = "MyAddress";
obj.Phone = 435345;
aList.Add(obj);
/// <summary>
/// Serialize the ArrayList
/// </summary>
/// <param name="obj"></param>
/// <returns></returns>
private string SerializeArrayList(ArrayList obj) {
System.Xml.XmlDocument doc = new XmlDocument();
Type[] extraTypes = new Type[1];
extraTypes[0] = typeof(MyBusinessObject);
System.Xml.Serialization.XmlSerializer serializer = new System.Xml.Serialization.XmlSerializer(typeof(ArrayList), extraTypes);
System.IO.MemoryStream stream = new System.IO.MemoryStream();
try {
serializer.Serialize(stream, obj);
stream.Position = 0;
doc.Load(stream);
return doc.InnerXml;
} catch { throw; } finally {
stream.Close();
stream.Dispose();
}
}
/// <summary>
/// DeSerialize serialized string
/// </summary>
/// <param name="serializedData"></param>
/// <returns></returns>
private ArrayList DeSerializeArrayList(string serializedData) {
ArrayList list = new ArrayList();
Type[] extraTypes = new Type[1];
extraTypes[0] = typeof(MyBusinessObject);
System.Xml.Serialization.XmlSerializer serializer = new System.Xml.Serialization.XmlSerializer(typeof(ArrayList), extraTypes);
XmlReader xReader = XmlReader.Create(new StringReader(serializedData));
try {
object obj = serializer.Deserialize(xReader);
list = (ArrayList)obj;
} catch { throw; } finally {
xReader.Close();
}
return list;
}
答案 1 :(得分:0)
为什么不将DateSerialize
存储为long
(日期的内部值,以毫秒为单位)?