Question

我正在尝试构建下一个存储过程，但它无法正常工作。

PREPARE STMT FROM 'SELECT a, b, c, d, e FROM TABLE_1 WHERE (`a` like `%?%` OR `b` like `%?%` OR `c` like `%?%` OR `d` like `%?%` OR `e` like `%?%`) LIMIT ?, ?';
EXECUTE STMT USING @search, @skip, @rows;

基本上，我正在尝试在其中一列中搜索一个字符串，并返回包含适合列的行。请帮我解决，因为我收到了下一个错误：

Unknown column '%?%' in 'where clause'

Answer 1

这是因为多少？应该等于USING子句后的参数数量。你也给错了报价？而不是"?"尝试：

PREPARE STMT FROM 'SELECT a, b, c, d, e FROM TABLE_1 WHERE (`a` like "%?%" OR `b` like "%?%" OR `c` like "%?%" OR `d` like "%?%" OR `e` like "%?%") LIMIT ?, ?';

EXECUTE STMT USING @search, @search, @search, @search, @search, @skip, @rows;

或尝试

SET @query1 = CONCAT('
    SELECT SQL_CALC_FOUND_ROWS a, b, c, d, e
    FROM TABLE_1
    WHERE (`a` like "%',@search,'%" OR
        `b` like "%',@search,'%" OR
        `c` like "%',@search,'%" OR
        `d` like "%',@search,'%" OR
        `e` like "%',@search,'%")
    LIMIT ',@skip,', ',@rows,'');

    PREPARE stmt FROM @query1; 
    EXECUTE stmt; 
    SELECT FOUND_ROWS() AS total_rows;
    DEALLOCATE PREPARE stmt;

Answer 2

mysql上的给定示例似乎显示了问号的数量应该与参数计数相似吗？

http://dev.mysql.com/doc/refman/5.0/en/sql-syntax-prepared-statements.html

我错了吗？

在您的情况下，这意味着七个问号以及七个参数。

一切顺利

Answer 3

试试这个......

PREPARE STMT FROM 'SELECT a, b, c, d, e FROM TABLE_1 WHERE (`a` like "%?%" OR `b` like "%?%" OR `c` like "%?%" OR `d` like "%?%" OR `e` like "%?%") LIMIT ?, ?';

EXECUTE STMT USING @search, @search, @search, @search, @search, @skip, @rows;

注意

变量数量应该等于我们拥有的问号数量。

你有7个问号，只有3个变量。所以错误来自第4 ?。

MYSQL - 准备stmt并执行stmt并添加WHERE和LIKE

3 个答案: