Question

使用jQ-ui的按钮功能

<script>
    $(function() {
        $( "#radio" ).buttonset();
    });
    </script>


    <div id="radio">
        <input type="radio" id="radio1" name="radio" /><label for="radio1">Choice 1</label>
        <input type="radio" id="radio2" name="radio" checked="checked" /><label for="radio2">Choice 2</label>
        <input type="radio" id="radio3" name="radio" /><label for="radio3">Choice 3</label>
    </div>

有没有办法一次取消选中buttonset的所有单选按钮？

Answer 1

您可以使用以下内容取消选中它们（针对jQuery UI 1.9进行了更新：

$('#radio input').removeAttr('checked');
// Refresh the jQuery UI buttonset.                  
$( "#radio" ).buttonset('refresh');

工作JSFiddle。

Answer 2

您可以匹配所有单选按钮，并使用prop()取消选中它们。

但是，您还必须在执行此操作后刷新buttonset小部件：

$("#radio").find("input:radio").prop("checked", false).end()
           .buttonset("refresh");

Answer 3

在jQuery 1.6版本之前

$(':radio').attr('checked', false);

OR

$(':radio').removeAttr('checked');

jQuery 1.6 +

之后

$(':radio').prop('checked', false);

OR

$(':radio').removeProp('checked');

Answer 4

偶然发现了这个...使用jQuery 1.9.1使用按钮组的类名，所有按钮最初都未设置。尚不确定是否会对此产生影响，但不方便知道。

$( "div.myclass" ).buttonset();

<div id="myDiv" class="myclass">
    <input type="radio" name="myname" id="id1" value="1"><label for="id1">Label1</label>
    <input type="radio" name="myname" id="id2" value="2"><label for="id2">Label2</label>
    <input type="radio" name="myname" id="id3" value="3"><label for="id3">Label2</label>
</div>

Answer 5

Javascirpt实现此目标的本机方法

function reset(){
//var list = document.querySelectorAll('input[type=radio]');
var list =document.querySelectorAll('input[type="radio"]:checked')
debugger
list.forEach(element => { 
if(element.checked){element.checked=false}}
    
);
}

<div id="myDiv" class="myclass">
    <input type="radio" name="myname" id="id1"  value="1"><label for="id1">Label1</label>
    <input type="radio" name="myname" id="id2" value="2"><label for="id2">Label2</label>
    <input type="radio" name="myname" id="id3" checked value="3"><label for="id3">Label3</label>
</div>

<button onclick="reset()">reset me</button>

Answer 6

这对我有用

$('input:radio[name="RadioName"]').each(function () { $(this).attr('checked', false); });

Answer 7

对于JQuery 1.12+

在DECLARE type sh_id is varray(10) of tab.col1%type; a_cnts number; b_cnts number; lv varchar2(20) := NULL; -- This is never modified in your code. ids sh_id := sh_id(1, 3, 5, 7, 9, 11, 13, 15, 17, 19); BEGIN FOR i IN 1 .. ids.COUNT LOOP SELECT count(b.sub_id) INTO b_cnts FROM tab a INNER JOIN tab1 b ON ( <some join conditions> ) -- you need to specify the join WHERE a.id = ids(i); INSERT INTO new_tab SELECT DISTINCT ids(i), b.sub_id, lv FROM tab a INNER JOIN tab1 b ON ( <some join conditions> ) -- you need to specify the join WHERE a.id = ids(i); -- Assuming you have a trigger to populate tab or tab1 from new_tab then a_cnts := b_cnts + SQL%ROWCOUNT; -- Otherwise: SELECT count(b.sub_id) INTO a_cnts FROM tab a INNER JOIN tab1 b ON ( <some join conditions> ) -- you need to specify the join WHERE a.id = ids(i); DBMS_OUTPUT.PUT_LINE( ids(i) || CHR(9) || b_cnts || CHR(9) || a_cnts ); END LOOP; -- Commit outside the loop COMMIT; END; /内包装单选按钮并为其指定一个ID（例如“ radio”）

DT: array[0..3] of TVarType = (varString, varInteger, varDouble, varBoolean);

一次取消选中所有JQuery单选按钮组

7 个答案: