Question

我正在解析一个txt文件，我在其中放置了模板（GUID）来帮助识别数据块...我在解析文件中的STRING变量时遇到了问题。解析时我正在使用一个迭代数据类型大小的DataPtr对象...问题是我无法正确计算字符串的大小以便（在读取字符串后）移动到下一个数据类型。这是一个要解析的示例文件：

xof 0303txt 0032

template Effect {
  <C7D92586-6C57-42d3-8F03-0BDF87EC1848>
  STRING filename;
}

template Light {
  <ADA248C7-97E3-4a42-A4C1-74EE8536FF37>
  DWORD type;
  array float position[3];
  array float direction[3];
  array float ambient[4];
  array float diffuse[4];
  array float specular[4];
  float power;
}

template Object {
  <B6494248-7D84-42d3-A4AA-0747E22E08D3>
  DWORD type;  
  array float position[3];
  array float orientation[4];
  STRING name;
  STRING filename;
}

Effect {
    ".//Data/Scene/TrainingRoom/Effects/effect.fx";
}

Light {
    1;
    -3.0; 1.0; -3.0;
    3.0; -1.0; 3.0;
    1.0; 1.0; 1.0; 1.0;
    1.0; 0.0; 0.0; 0.0;
    1.0; 1.0; 1.0; 1.0;
    0.1;
}

Object {
    1;
    0.0; 0.0; 0.0;
    0.0; 0.0; 0.0; 1.0;
    ".//Data/Scene/TrainingRoom/TrainingRoom.x";
}

以下是当前正在运行的代码示例（无字符串标记）：

if(CompareDataObjectType(pDataObj, TID_D3DRMLightCustom))
    {
        D3DXVECTOR3 *vecPtr = NULL;
        D3DXVECTOR4 *colorPtr = NULL;
        DWORD *DataPtr = (DWORD*)GetObjectData(pDataObj); // Data Pointer points at 1st data location
        m_light.type = *DataPtr++;  
        vecPtr = (D3DXVECTOR3*)DataPtr;
        m_light.position = *vecPtr;
        DataPtr+=3; 
        vecPtr = (D3DXVECTOR3*)DataPtr;
        m_light.direction = *vecPtr;
        DataPtr+=3;
        colorPtr = (D3DXVECTOR4*)DataPtr;
        m_light.ambient = *colorPtr;
        DataPtr+=4;
        colorPtr = (D3DXVECTOR4*)DataPtr;
        m_light.diffuse = *colorPtr;
        DataPtr+=4;
        colorPtr = (D3DXVECTOR4*)DataPtr;
        m_light.specular = *colorPtr;
        DataPtr+=4;
        float *fPtr = (float*)DataPtr;
        m_light.power = *fPtr;
        return true;
    }

这一切都没关系......以下内容返回错误结果：

if(CompareDataObjectType(pDataObj, TID_D3DRMObject))
    {
        D3DXVECTOR3 *vecPtr = NULL;
        D3DXQUATERNION *quatPtr = NULL;
        DWORD *DataPtr = (DWORD*)GetObjectData(pDataObj);       
        m_object.type = *DataPtr++; 
        vecPtr = (D3DXVECTOR3*)DataPtr;
        m_object.position = *vecPtr;
        DataPtr+=3;     
        quatPtr = (D3DXQUATERNION*)DataPtr;
        m_object.orientation = *quatPtr;
        DataPtr+=4;
        m_object.name = (LPCSTR)DataPtr;
        size_t length = strlen(m_object.name);
        DataPtr+=length;
        m_object.filename = (LPCSTR)DataPtr; // filename only contains a portion of the correct string...
        return true;
    }

Answer 1

如果输入数据包含空终止字符串，则表示以下内容：

size_t length = strlen(m_object.name);
DataPtr+=length;

应该考虑空字符：

size_t length = strlen(m_object.name);
DataPtr += length + 1;

解析文本文件以提取字符串

1 个答案: