为什么在python中阻塞模式中没有阻止recv函数

时间:2012-07-30 09:15:22

标签: python sockets

我遇到套接字编程问题,并且多次查找错误,但是没有找到。请有人帮助我。

服务器代码:

 import socket
 server_socket = socket.socket(socket.AF_INET,socket.SOCK_STREAM)
 server_socket = socket.socket(socket.AF_INET,socket.SOCK_STREAM)
 server_socket.bind(("localhost",5001)
 server_socket.listen(10)
 client_socket, address = server_socket.accept() 
 server_socket = socket.socket(socket.AF_INET,socket.SOCK_STREAM)
 server_socket.bind(("localhost",5001))
 server_socket.listen(10)
 client_socket, address = server_socket.accept()
 while True:
     temp = client_socket.recv(100)
     print (len(temp))
     print ("Recv isn't blocked")
 client_socket.close()

客户代码:

import socket
import io

client_socket = socket.socket(socket.AF_INET,socket.SOCK_STREAM)
client_socket.connect(("localhost",5001))
print("send data finised")

当我运行程序时,虽然客户端没有向服务器发送任何内容,但是服务器上的recv()函数仍在运行,我无法理解为什么,请帮帮我。

1 个答案:

答案 0 :(得分:0)

因为您的客户端程序退出,套接字关闭了吗?

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