Question

我有一个带有textField的inputView的UIPickerView显示。我已将pickerView拆分为两列。一个是整数50-500。另一个是0.25,0.50,0.75。我希望他们能够选择整数，然后用另一列选择数字的小数部分。我无法弄清楚如何显示“完整”号码。当我移动第二列时，它只是将其注册为移动第一列并更改整数。我希望用户能够选择整数，数字的小数部分，完成命中，textField显示格式为“100.25”的数字或他们选择的任何数字。我有完成按钮编码...并且整个数字只显示格式，即“100”。

谢谢！

UPDATE !!! CODE !!!!

-(void)pickerView:(UIPickerView *)pickerView didSelectRow:(NSInteger)row inComponent:  (NSInteger)component{
if ([pickerView isEqual:weightPickerView]) {
    weightField.text = [NSString stringWithFormat:@"%d.%d",[weightPickerArray   objectAtIndex:row], [weightPickerArray2 objectAtIndex:row]];



-(void)populateWeightPickerArray{
weightPickerArray = [[NSMutableArray alloc] init];
for (int weight = 50; weight <=500; weight++) {
    NSString *weightString = [NSString stringWithFormat:@"%d%",weight];
    [weightPickerArray addObject:weightString];
}
}

-(void)populateWeightPickerArray2{
weightPickerArray2 = [[NSMutableArray alloc] init];
[weightPickerArray2 addObject:@"0.25"];
[weightPickerArray2 addObject:@"0.50"];
[weightPickerArray2 addObject:@"0.75"];
}

所以我希望用户选择他们的体重 - 例如100表示第1列，第2列表示0.25。然后我希望文本字段显示100.25 ...

更新2！更改了代码，现在我收到错误..

[会议开始于2012-08-03 10:39:39 -0500。] 2012-08-03 10：39：45.656 CalorieAppFinal [1088：207] - [NSCFNumber isEqualToString：]：无法识别的选择器发送到实例0x4b336c0 2012-08-03 10：39：45.661 CalorieAppFinal [1088：207] *由于未捕获的异常'NSInvalidArgumentException'终止应用程序，原因：' - [NSCFNumber isEqualToString：]：无法识别的选择器发送到实例0x4b336c0' * 首次调用堆栈

这是我如何初始化我的weightPicker

 -(IBAction)weightFieldDidBeginEditing{
weightPickerView = [[UIPickerView alloc] init];
weightField.inputView = weightPickerView;
weightPickerView.showsSelectionIndicator = YES;
weightPickerView.delegate = self;
weightPickerView.dataSource = self;
[weightPickerView release];
}


-(void)pickerView:(UIPickerView *)pickerView didSelectRow:(NSInteger)row inComponent:(NSInteger)component{

if ([pickerView isEqual:weightPickerView]) {
    int valOne = [[weightPickerArray objectAtIndex:row] intValue];
    CGFloat valTwo = [[weightPickerArray2 objectAtIndex:row] floatValue];
    weightField.text = [NSString stringWithFormat:@"%d.%.2f",valOne, valTwo];
}


-(void)populateWeightPickerArray{
weightPickerArray = [[NSMutableArray alloc] init];
for (int weight = 50; weight <=500; weight++) {
    [weightPickerArray addObject:[NSNumber numberWithInt:weight]];
}
 }

-(void)populateWeightPickerArray2{
weightPickerArray2 = [[NSMutableArray alloc] init];
[weightPickerArray2 addObject:[NSNumber numberWithFloat:0.25f]];
[weightPickerArray2 addObject:[NSNumber numberWithFloat:0.50f]];
[weightPickerArray2 addObject:[NSNumber numberWithFloat:0.75f]];
 }

Answer 1

**编辑为第一个答案有点令人困惑

在字符串中显示浮点数或十进制数时，您有两种常用方法。

stringWithFormat
stringByAppendingFormat

因此，如果您有两个列/选择器触发两个单独的方法，或者如果您触发相同的方法但检查特定的选择器，则可以执行此操作：

- (void)somePickerDidChangeValueMethod:(UIPicker)picker
{
    //If you have on float value
    myTextField.text = [NSString stringWithFormat:@"%.2f",yourFloatValue];
            //the %.xf represents how many decimal places to show
    //If you have two int values
    myTextField.text = [NSString stringWithFormat:@"%d.%d",int1,int2];


    //If incoming number is a float
    myTextField.text = [myTextField.text stringByAppendingFormat:@".%.0f",yourFloatValue];
    //If incoming number is an int
    myTextField.text = [myTextField.text stringByAppendingFormat:@".%d",intVal];
}

希望这有帮助。

Answer 2

你可以使用下面的答案，但是，如果你打算稍后使用某些数学中的值，那么从长远来看使用NSNumber可能更容易。由你决定 - 两者都可以。

-(void)pickerView:(UIPickerView *)pickerView didSelectRow:(NSInteger)row inComponent:(NSInteger)component
{
    if ([pickerView isEqual:weightPickerView])
    {
        int valOne = [[weightPickerArray objectAtIndex:row] intValue];
        CGFloat valTwo = [[weightPickerArray2 objectAtIndex:row] floatValue];
        weightField.text = [NSString stringWithFormat:@"%d.%.2f",valOne,valTwo];
    }
}


-(void)populateWeightPickerArray
{
    weightPickerArray = [[NSMutableArray alloc] init];
    for (int weight = 50; weight <=500; weight++)
    {
        //easier to store NSNumberWithInt as opposed to a string
        [weightPickerArray addObject:[NSNumber numberWithInt:weight]];
    }
}

-(void)populateWeightPickerArray2
{
    weightPickerArray2 = [[NSMutableArray alloc] init];
    [weightPickerArray2 addObject:[NSNumber numberWithFloat:0.25f]];
    [weightPickerArray2 addObject:[NSNumber numberWithFloat:0.50f]];
    [weightPickerArray2 addObject:[NSNumber numberWithFloat:0.75f]];
}

尝试类似的东西。

希望它有所帮助。

如何使用具有多个列的UIpickerView填充TextField？

2 个答案: