Question

Hotel_id   Room_id   Room_type   Start_date   End_date     Price
----------------------------------------------------------------
   13        2        standard   2012-08-01   2012-08-15   7000
   13        2        standard   2012-08-16   2012-08-31   7500
   13        2        standard   2012-09-01   2012-09-30   6000
   13        3         luxury    2012-08-01   2012-08-15   9000
   13        3         luxury    2012-08-16   2012-08-31   10000
   13        3         luxury    2012-09-01   2012-09-30   9500

嗨，这是我桌子的结构和数据。

我需要为酒店预订创建一个mysql查询，该查询将匹配数据库用户输入的数据：

他们想要签入和结帐的日期
房间类型

对于Ex：

如果用户根据这些日期选择带豪华房的酒店（2012-08-30至2012-09-04） 8月30日和31日的总费用为（10000 * 2）+ 9月1日，2日和3日（9500 * 3）（不包括第4个结账日）这意味着总价将为20000 + 28500 = 48500

因此查询应根据Hotel_id，Room_id，Start_date，End_date和Price

由于

Answer 1

使用此解决方案：

SELECT     SUM(
               CASE WHEN a.Start_date = b.min_sd AND a.Start_date <> b.max_sd THEN
                        (DATEDIFF(a.End_date, '2012-08-30')+1) * a.Price
                    WHEN a.Start_date = b.max_sd AND a.Start_date <> b.min_sd THEN
                        DATEDIFF('2012-09-04', a.Start_date) * a.Price
                    WHEN (a.Start_date,a.Start_date) IN ((b.min_sd,b.max_sd)) THEN
                        (DATEDIFF('2012-09-04', '2012-08-30')+1) * a.Price
                    WHEN a.Start_date NOT IN (b.min_sd, b.max_sd)             THEN
                        (DATEDIFF(a.End_date, a.Start_date)+1) * a.Price
               END 
           ) AS totalprice
FROM       rooms a
CROSS JOIN (
           SELECT MIN(Start_date) AS min_sd,
                  MAX(Start_date) AS max_sd
           FROM   rooms
           WHERE  Room_type   = 'luxury'     AND
                  End_date   >= '2012-08-30' AND
                  Start_date <= '2012-09-04'
           ) b
WHERE      a.Room_type   = 'luxury'     AND
           a.End_date   >= '2012-08-30' AND
           a.Start_date <= '2012-09-04'

分别用输入的开始日期和结束日期替换2012-08-30和2012-09-04的出现。

这将考虑同一个月的开始和结束日期以及跨越多个月。

SQLFiddle Demo

Answer 2

你可以使用MySQL的BETWEEN ... AND ... 操作员找到所需预订的日期范围（记得从给定的结账中休息一天）日期，就像你说的，没有夜间住宿），然后按房间分组结果并采取 SUM()价格乘以夜数（可以使用MySQL的LEAST()和。来计算 GREATEST()函数）：

SELECT   Room_id,
         SUM(Price * (1 + DATEDIFF(
              LEAST(End_date,   '2012-09-04' - INTERVAL 1 DAY),
           GREATEST(Start_date, '2012-08-30')
         ))) AS Total
FROM     mytable
WHERE    Room_type = 'luxury' AND (
              '2012-09-04' - INTERVAL 1 DAY
                           BETWEEN Start_date AND End_date
           OR '2012-08-30' BETWEEN Start_date AND End_date
         )
GROUP BY Room_id

在sqlfidde上查看。

Answer 3

试试这个：

set @Hotel_id :=13;
set @Room_id :=3;
set @Start_date :='2012-08-30'  ;
set @End_date :='2012-09-04';

 select sum(b.TotalPrice-b.deductions) as total_cost from
( select a.Price,a.StartDate,a.EndDate,price*(DATEDIFF(a.EndDate,a.StartDate)+1) as TotalPrice  
 ,case when a.EndDate=@End_date then a.Price else 0 end as deductions
 from
(select price,case when @Start_date>=Start_date then  @Start_date else Start_date end as StartDate
,case when @End_date<=End_date then  @End_date else End_date end as EndDate
 from h_booking h1 
where  Hotel_id=@Hotel_id
and Room_id=@Room_id
and (@Start_date between Start_date and End_date or @End_date between Start_date and End_date ))a )b

计算给定日期之间的价格

3 个答案: