Question

如何简化IF部分以便于理解？

for (i = list.length - 2; i >= 0; i -= 2) {
    if (!(callback && list[i] !== callback || context && list[i + 1] !== context)) {
        list.splice(i, 2);
    }
}

Answer 1

var noCallback = callback && list[i] !== callback;
var noContext = context && list[i + 1] !== context;
if(! noCallback && ! noContext){...}

或者删除评论中建议的否定：

var callbackCheck = !callback || list[i] === callback;
var contextCheck = !context || list[i + 1] === context;
if(callbackCheck && contextCheck ){...}

Answer 2

一些布尔数学：

!(callback && list[i] !== callback || context && list[i + 1] !== context)
!(!(!callback || list[i] === callback) || !(!context || list[i + 1] === context))
(!callback || list[i] === callback) && (!context || list[i + 1] === context)

我认为disjunctive normal form比被否定的conjunctive normal form更容易理解。

为了使单个部分更容易理解，请使用说话变量名称（我不知道其范围，你可能会找到更好的东西）：

var rightCallback = !callback || list[i] === callback;
var rightContext = !context || list[i + 1] === context;
if (rightCallback && rightContext) {…}

Answer 3

我建议将语句封装到带有描述性名称的函数中（我不明白你想做什么），然后调用

if (true == meaningfulConditionName(list, callback))
{
    list.splice(i, 2);
}

Answer 4

不能简化为：

for (i = list.length - 2; i >= 0; i -= 2) callback && list[i] !== callback || context && list[i + 1] !== context || list.splice(i, 2)

Answer 5

这是我的版本，通过了所有Backbone.js测试，并且比原来的

慢

  if(
      // callback defined, context is null
      // remove callback for all context
      ( callback && list[i] === callback
         && !context)

      // callback defined and context is defined
      // ie remove specified callback for specified context
      || ( callback && list[i] === callback
           && context && list[i+1] === context)

      // callback NOT defined and context is defined
      // ie removed all callback for specific context
      || ( !callback && list[i] !== callback
           && context && list[i+1] === context )

      // callback NOT defined and context NOT defined
      // i.e. removed everything, this is unreachable code
      // as it is caught by 
      // https://github.com/documentcloud/backbone/blob/master/backbone.js#L112
      // and https://github.com/documentcloud/backbone/blob/master/backbone.js#L103
      || ( !callback && !context )

      ) {

            // remove callback and context
            list.splice( i, 2 );
  }

简化复杂的if语句

5 个答案: