具有复合主键的另一个表中的INSERT或UPDATE表

时间:2012-08-09 12:16:10

标签: sql sql-server sql-server-2005

我正在寻找正确的语法以及直接从SQL执行以下操作的方法:从TableMain中包含的数据中插入或更新(如果数据已经存在)TableA,两者都具有相同的复合主要键。

两个表都定义为:

CREATE TABLE TableA (
[TID0] [int] NOT NULL,
[TID1] [int] NOT NULL,
[language] [nvarchar](2) NOT NULL,
[TID2] [nvarchar](200) NOT NULL,
[text] [nvarchar](max) NULL,
[updatedOn] [datetime] NOT NULL  DEFAULT (getdate())
PRIMARY KEY (
    [TID0],
    [TID1],
    [language],
    [TID2],
)
) ON [PRIMARY] TEXTIMAGE_ON [PRIMARY]

TableA将定期删除并填写。

TableMain作为相同的定义,但将包含更多行数据,我需要的是将TableA中从未见过的值插入TableMain,并更新已存在的行。< / p>

我曾经做过这种插入,但我不知道如何处理更新和复合主键:

INSERT INTO TableMain 
    SELECT * FROM TableA

编辑:我正在使用 SQL Server 9.00.5000

编辑:另一种受MERGE和mimick it

启发的方式
DECLARE @updatedIDs TABLE(
    [TID0] [int],
    [TID1] [int],
    [language] [nvarchar](2),
    [TID2] [nvarchar](200),
                PRIMARY KEY ([TID0], [TID1], [language], [TID2])  -- as stated by Nikola Markovinović above, thanks
);

-- First update records 
update TableMain 
   set [text]      = source.[text], 
       [updatedOn] = source.[updatedOn] 
       OUTPUT
         inserted.[TID0]
         inserted.[TID1]
         inserted.[language]
         inserted.[TID2]
       INTO @updatedIDs
  from 
       TableMain AS main
       , TableA AS source 
  WHERE    
   TableMain.[TID0]         = source.[TID0] 
   and TableMain.[TID1]     = source.[TID1] 
   and TableMain.[language] = source.[language] 
   and TableMain.[TID2]     = source.[TID2] 

-- And then insert 

insert into TableMain
select *
  from TableA AS source 
 where not exists 
       ( 
      select 1
        from @updatedIDs AS i
       where i.[TID0]     = source.[TID0] 
         and i.[TID1]     = source.[TID1] 
         and i.[language] = source.[language] 
         and i.[TID2]     = source.[TID2] 
       )

3 个答案:

答案 0 :(得分:5)

您应该使用merge声明

类似的东西:

merge TableMain  AS target
using TableA as source 
ON <join tables here>
WHEN MATCHED THEN <update>
WHEN NOT MATCHED BY TARGET <Insert>
WHEN NOT MATCHED BY SOURCE <delete>

答案 1 :(得分:4)

以下是您可能用于插入数据的脚本:

-- On error transaction is automatically rolled back
set xact_abort on

begin transaction
-- First update records
update TableMain
   set [text]      = source.[text],
       [updatedOn] = source.[updatedOn]
  from TableMain
 inner join TableA source
    on TableMain.[TID0]     = source.[TID0]
   and TableMain.[TID1]     = source.[TID1]
   and TableMain.[language] = source.[language]
   and TableMain.[TID2]     = source.[TID2]

-- And then insert

insert into TableMain ([TID0], [TID1], [language], [TID2], [text], [updatedOn])
select [TID0], [TID1], [language], [TID2], [text], [updatedOn]
  from TableA source
 where not exists
       (
          select *
            from TableMain
           where TableMain.[TID0]     = source.[TID0]
             and TableMain.[TID1]     = source.[TID1]
             and TableMain.[language] = source.[language]
             and TableMain.[TID2]     = source.[TID2]
       )

commit transaction

如果效果不理想,您可能会将not exists()重写为left join ... where TableMain.TID0 is null

答案 2 :(得分:3)

您可以使用SQLServer 2008中的Merge命令。它允许您将来自其他数据源的数据合并到主数据源中,并在存在密钥匹配时定义特定行为(您可能希望更新您的表格)或不匹配,您将要插入新记录。

http://blog.sqlauthority.com/2010/06/08/sql-server-merge-operations-insert-update-delete-in-single-execution/

您可以访问此链接以获取少量代码示例。

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