通过文件上传获取准确的文件路径,通过电子邮件C#ASP.NET发送文件

时间:2012-08-09 20:17:54

标签: c# asp.net email file-upload path

我想通过电子邮件使用c#ASP.net发送文件(也许还有更多文件,但目前我担心发送至少一个文件)

目前,如果您想发送电子邮件,我确实有一种方法可行。

public string EnviarMensaje(int intIdVendedor, string strCorreoPara, string strCorreosAdicionales, string strTema, string strMensaje, string strRuta)
    {
        string strResultado="";
        DataTable dt = ConexionBD.GetInstanciaConexionBD().GetVendedorEspecifico(intIdVendedor);
        string strCuerpo = strMensaje + "\n\n\n\nMensaje Enviado Por:\n" + dt.Rows[0]["Vendedor"] + "\n" + dt.Rows[0]["Email"] + "\n" + dt.Rows[0]["Telefono"];
        string[] strListaCorreos = strCorreosAdicionales.Split(new Char[] {' ', ','}, StringSplitOptions.RemoveEmptyEntries);

        try
        {
            MailMessage mail = new MailMessage();
            SmtpClient SmtpServer = new SmtpClient("smtpout.secureserver.net");

            mail.Subject = strTema;
            mail.Body = strCuerpo;
            mail.From = new MailAddress(strCorreoDe);
            mail.To.Add(strCorreoPara);

            foreach (string c in strListaCorreos)
            {
                mail.To.Add(c);
            }

            if (strRuta != "")
            {
                Attachment attachment;
                attachment = new Attachment(strRuta);
                mail.Attachments.Add(attachment);
            }

            SmtpServer.Port = 80;
            SmtpServer.Credentials = new System.Net.NetworkCredential(strCorreoDe, strContrasena);
            SmtpServer.EnableSsl = false;

            SmtpServer.Send(mail);
            strResultado = "Exito";
        }

        catch (Exception ex)
        {
            strResultado = ex.ToString();
        }

        return strResultado;
    }

在aspx中我有

<asp:FileUpload ID="fileUploadArchivos" runat="server" />

<asp:ImageButton ID="imgBtnEnviar" runat="server" Height="60px" Width="60px" ImageUrl="~/img/iconos/email.png" CausesValidation = "True" ValidationGroup="vgpCorreo" onclick="imgBtnEnviar_Click" />

和我有的cs

EnviarEmail objEmail = new EnviarEmail();

protected void imgBtnEnviar_Click(object sender, ImageClickEventArgs e)
{
if (fileUploadArchivos.HasFile)
{
    strArchivo = Path.GetTempFileName();\\RIGHT NOW I LEFT IT THIS WAY, BUT I NOW THAT HERE IS THE PROBLEM, I DON'T KNOW WHTAT CAN I DO HERE
}
string strResultado = objEmail.EnviarMensaje((int)Session["IdVendedor"], lblCorreoPara.Text, tbxCorreoPara.Text, tbxTema.Text, tbxMensaje.Text, strArchivo);

}

但是,问题出在FileUpload中。 我尝试了很多方法,比如Server.MapPath,Path.GetFileName,GetDirectoryName,GetFullPath,GetPathRoot ...而且我总是得到什么,只有文件名或完全不同的路径(我猜是服务器类路径) ..

我目前只想获得一个像C:\ Test.txt这样简单的文件路径... 我想如果我能从FileUpload中获取那个确切的字符串,我就能发送它......但是,我无法弄清楚如何让它工作。

希望你能帮助我 感谢

3 个答案:

答案 0 :(得分:1)

如果您需要保存在服务器上的文件的本地副本,您可以这样做

fuFileUpload.SaveAs(MapPath(filepath));

然后你的strRuta可以使用你刚刚保存的文件

strRuta = Server.MapPath(filepath);

准备好传入新的附件对象。

答案 1 :(得分:0)

您无需将文件保存在所有到磁盘,如果您只想将其添加为附件,则无需将其添加。

FileUpload的{​​{3}}属性为Stream - FileContent类的某些构造函数将流作为参数。

解决方案是将此流传递给您的方法并直接使用它。

在代码背后:

string strResultado = objEmail.EnviarMensaje((int)Session["IdVendedor"], 
                                             lblCorreoPara.Text, 
                                             tbxCorreoPara.Text, 
                                             tbxTema.Text, 
                                             tbxMensaje.Text, 
                                             fileUploadArchivos.FileContent);

在你班上:

public string EnviarMensaje(int intIdVendedor, 
                            string strCorreoPara, 
                            string strCorreosAdicionales, 
                            string strTema, 
                            string strMensaje, 
                            Stream attachmentData)
{

...

  var attachment = new Attachment(attachmentData, "nameOfAttachment");

...

}

答案 2 :(得分:0)

您可以尝试使用流而不是简单文本:

public string EnviarMensaje(int intIdVendedor, string strCorreoPara, string strCorreosAdicionales, string strTema, string strMensaje, string strRuta)
    {
        string strResultado="";
        DataTable dt = ConexionBD.GetInstanciaConexionBD().GetVendedorEspecifico(intIdVendedor);
        string strCuerpo = strMensaje + "\n\n\n\nMensaje Enviado Por:\n" + dt.Rows[0]["Vendedor"] + "\n" + dt.Rows[0]["Email"] + "\n" + dt.Rows[0]["Telefono"];
        string[] strListaCorreos = strCorreosAdicionales.Split(new Char[] {' ', ','}, StringSplitOptions.RemoveEmptyEntries);

        try
        {
            MailMessage mail = new MailMessage();
            SmtpClient SmtpServer = new SmtpClient("smtpout.secureserver.net");

            mail.Subject = strTema;
            mail.Body = strCuerpo;
            mail.From = new MailAddress(strCorreoDe);
            mail.To.Add(strCorreoPara);

            foreach (string c in strListaCorreos)
            {
                mail.To.Add(c);
            }

            bool hasAttachment = !string.IsNullOrWhitespace(strRuta);
            System.IO.FileStream stream = null;
            Attachment attachment = null;

            if (hasAttachment)
            {
                // Create a file stream.
                stream = new FileStream(strRuta, FileMode.Open, FileAccess.Read);

                // Define content type.
                ContentType contentType = new ContentType();
                contentType.MediaType = MediaTypeNames.Text.Plain; // or whatever your attachment is

                // Create the attachment and add it.
                attachment = new Attachment(stream, contentType);
                mail.Attachments.Add(attachment);
            }

            SmtpServer.Port = 80;
            SmtpServer.Credentials = new System.Net.NetworkCredential(strCorreoDe, strContrasena);
            SmtpServer.EnableSsl = false;

            SmtpServer.Send(mail);
            strResultado = "Exito";

            // Don't forget to release the resources if the attachment has been added
            if (hasAttachment)
            {
                data.Dispose();
                stream.Close();
                stream.Dispose();
            }
        }

        catch (Exception ex)
        {
            strResultado = ex.ToString();
        }

        return strResultado;
    }