我有一个警报,将在下午5:30准确触发。我想让日期动态,我的意思是它将获得系统日期。因为您可以在我的代码中看到,它只会在我指定的日期获得时间。谢谢!
function alert5pm() {
alert("It's already 5:30 pm and you only have 30 minutes left before to log-out");
}
var timeAt3pm = new Date("8/10/2012 05:30:00 PM").getTime()
, timeNow = new Date().getTime()
, offsetMillis = timeAt3pm - timeNow;
setTimeout('alert5pm()', offsetMillis);
例如:
创建日期实例以获取系统日期和时间: var dateToday = new date();
从这里开始,如何提取特定时间。例如,我需要指明我需要在今天系统日期的下午5:30获得时间。就像我的代码一样。但是正如你所看到的,它只能在2012年10月8日获得时间。我希望它使用系统日期和时间。有什么想法吗?
答案 0 :(得分:0)
如果你想让日期可配置并从服务器端设置它,我建议你对服务器进行ajax调用来获取时间和日期并在javascript函数中设置值
var time = ""
function alert5pm() {
alert("It's already 5:30 pm and you only have 30 minutes left before to log-out");
}
if( time == ""){
$.ajax({
type: "POST",
url: "some_server_url_to_fetch_data",
data: "{}",
contentType: "application/json; charset=utf-8",
dataType: "json",
success: function(msg) {
time = msg.data;
var timeAt3pm = new Date(time).getTime();
var timeNow = new Date().getTime()
var offsetMillis = timeAt3pm - timeNow;
setTimeout('alert5pm()', offsetMillis);
}
});
}
else{
var timeAt3pm = new Date(time).getTime();
var timeNow = new Date().getTime()
var offsetMillis = timeAt3pm - timeNow;
setTimeout('alert5pm()', offsetMillis);
}
}
答案 1 :(得分:0)
我认为你需要类似下面的代码:
function todayAt(hours,minutes)
{
var today = new Date();
today.setHours(hours);
today.setMinutes(minutes);
today.setSeconds(0);
return today;
}
alert(todayAt(17,30));
作为下一步,您可以改进功能并以您想要的任何格式传递参数(例如,在“5:30 AM”字符串中。
所以你将拥有以下代码:
function alert5pm() {
alert("It's already 5:30 pm and you only have 30 minutes left before to log-out");
}
function todayAt(hours,minutes)
{
var today = new Date();
today.setHours(hours);
today.setMinutes(minutes);
today.setSeconds(0);
return today;
}
var targetTime= todayAt(17,30);
var offsetMillis = targetTime - Date.now();
setTimeout('alert5pm()', offsetMillis);