将日期从格式转换为另一种格式

时间:2012-08-13 14:55:25

标签: php date datetime format date-format

  

可能重复:
  Convert one date format into another in PHP

我有一个用户格式的日期和使用PHP日期格式(http://fr.php.net/manual/en/function.date.php)的对应格式。用户输入前不知道此格式。

我必须将此日期转换为已知格式,例如'd / m / Y h:i:s'。 我的PHP服务器使用5.2.1 PHP版本,所以我不能使用DateTime类。

有人可以选择DateTime :: createFromFormat方法,这样做的脚本或想法可以帮助我吗?

祝你好运, 弗洛里安。

修改:

我编写了一个函数,用于将日期转换为其他格式而不知道原始日期格式:

/**
 * This function converts a date with unknown format into a defined format.
 * It could detect some standard date formats : dd/mm/YYYY, dd-mm-YY, YYYY-mm-dd hh:mm:ss, etc.
 * @param string $date date which is user formatted.
 * @param int $options used to help algorithm to detect date format : US or FR date, past date or future date, hour format.
 * @param string $newFormat format the date must be converted into
 * @param string $originalFormat format detected
 * @return boolean|string the new date, corresponding to the $date argument, formatted into the $newFormat format
 */
function convertDateToFormat($date, $options = 0, $newFormat, &$originalFormat = ''){
    if($options == 0){
        $options = DATE_FR | DATE_PAST | HOUR_24;
    }
    $matches = array();

    $year = 0;
    $month = 0;
    $day = 0;
    $hour = 0;
    $minute = 0;
    $second = 0;

    $originalFormatOk = false;

    if(preg_match('#(\d{1,2})([/.-])(\d{1,2})(([/.-])(\d{2,4}))?#', $date, $matches)){
        if(isset($matches[6])){
            if(strlen($matches[6]) == 2){
                if($matches[6] >= date('y') && DATE_PAST)
                    $year = '19'.$matches[6];
                else
                    $year = '20'.$matches[6];
                $originalFormatyear = 'y';
                if($options & DATE_US){
                    $originalFormat = 'm'.$matches[2].'d'.$matches[5].$originalFormatyear;
                    $year = $matches[6];
                    $month = $matches[1];
                    $day = $matches[3];
                    $originalFormatOk = true;
                }
            }
            else{
                $year = $matches[6];
                $originalFormatyear = 'Y';
            }
            if(!$originalFormatOk){
                $year = $matches[6];
                $month = $matches[3];
                $day = $matches[1];
                $originalFormat = 'd'.$matches[2].'m'.$matches[5].$originalFormatyear;
                $originalFormatOk = true;
            }
        }
        else{
            if($options & DATE_US){
                $originalFormat = 'm'.$matches[2].'d';
                $year = date('Y');
                $month = $matches[1];
                $day = $matches[3];
            }
            else{
                $originalFormat = 'd'.$matches[2].'m';
                $year = date('Y');
                $month = $matches[3];
                $day = $matches[1];
            }
            $originalFormatOk = true;
        }

    }

    if(preg_match('#'.$matches[0].'(\D*)(\d{1,2})([:hH])(\d{1,2})(:(\d{1,2}))?#', $dateHour, $matches)){
        if($options & HOUR_12)
            $originalFormatHour = 'h';
        else
            $originalFormatHour = 'H';
        $hour = $matches[2];
        $minute = $matches[4];
        if(strtolower($matches[3]) == 'h')
            $matches[3] = '\\'.$matches[3];
        $originalFormat .= $matches[1].$originalFormatHour.$matches[3].'i';
        if(isset($matches[6])){
            $second = $matches[6];
            $originalFormat .= ':s';
        }
    }

    if($originalFormatOk)
        return date($newFormat, mktime($hour, $minute, $second, $month, $day, $year));
    return false;
}

1 个答案:

答案 0 :(得分:2)

date_parse_from_format()功能可以完成您需要的一切。

E.g。 (来自文档):

$date = "6.1.2009 13:00+01:00";
print_r(date_parse_from_format("j.n.Y H:iP", $date));

但是,如果你知道格式,那或多或少粗略猜测你必须使用类似date_parse()的东西,它会给你(希望)一个正确的日期但是可能会失败。

E.g。 (来自文档):

print_r(date_parse("2006-12-12 10:00:00.5"));

将打印:

Array
(
    [year] => 2006
    [month] => 12
    [day] => 12
    [hour] => 10
    [minute] => 0
    [second] => 0
    [fraction] => 0.5
    [warning_count] => 0
    [warnings] => Array()
    [error_count] => 0
    [errors] => Array()
    [is_localtime] => 
)