Question

我有以下json数据，它位于网址http://localhost/stock/index.php/masterfiles/itemgriddata

中

[{"name":"asdasd","code":"123","id":"1","unit":"Nos","purprice":"25000"},{"name":"Item2","code":"1235","id":"2","unit":"Nos","purprice":"0"}]

我想获得name和code的值id等于1，并使用jquery将它们存储为变量。

我知道有一种方法，

$.getJSON('http://localhost/stock/index.php/masterfiles/itemgriddata', function(data) {
  console.log(data);
});

但我不知道如何实现它。任何人都可以帮我找到解决方案吗？

Answer 1

$.getJSON('http://localhost/stock/index.php/masterfiles/itemgriddata', function(data) {
  $.each(data, function(index, val) {
      if( val.id == '1'){
        var name = val.name,
            code = val.code,
            unit = val.unit,
            purprice = val.purprice,
            id = val.id;
      }
  })
});

但是如果你想将所有结果存储在数组中，那么：

var dataarr = [];
$.getJSON('http://localhost/stock/index.php/masterfiles/itemgriddata', function(data) {
  $.each(data, function(index, val) {
      if( val.id == '1'){
        dataarr.push(
            val.name,
            val.code,
            val.unit,
            val.purprice,
            val.id;
       );
  })
});

有关详细信息，请参阅 doco 。

Answer 2

您可以迭代数组并检查id为“1”的对象为

arr = [{"name":"asdasd","code":"123","id":"1","unit":"Nos","purprice":"25000"},{"name":"Item2","code":"1235","id":"2","unit":"Nos","purprice":"0"}]

$.each(arr, function(i,ele){
 if (ele.id =="1"){
  alert(ele.name)
  alert(ele.code)
 }
});

Answer 3

您可以尝试以下内容：

$.getJSON('http://localhost/stock/index.php/masterfiles/itemgriddata', function(data) {
  var results = [];

  $.each(data, function(key, val) {
    if (val.id === "1") {
        results.push(val.name);
        results.push(val.code);
    }
  });
  // Then you can do whatever you want to do with results
});

Answer 4

请阅读此链接上提供的文件

jQuery.getJSON()

使用jquery从Json获取数据

4 个答案: