我的SQL:
CREATE PROCEDURE INV_MIN_PURCHASE_PRICE()
BEGIN
DECLARE done INT;
DECLARE current_inventory_ID INT;
DECLARE cur1 CURSOR FOR SELECT inventory_ID FROM _inventory;
DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = 1;
SET done = 0;
OPEN cur1;
REPEAT
FETCH cur1 INTO current_inventory_ID;
UPDATE _debug SET rows=rows+1;
UNTIL done
END REPEAT;
CLOSE cur1;
END;
当我调用此过程时,MySQL只获取一行(_debug rows
增加1)。为什么??这是一个错误吗?
答案 0 :(得分:13)
我在MySQL中遇到了与存储过程相同的问题。它应该从表中获取某个列中具有空值的所有记录,然后从另一个表中填充该值。然而,它在一条记录后停止了:
CREATE PROCEDURE `updateRecord`()
BEGIN
DECLARE done INT DEFAULT FALSE;
DECLARE recordId, newValue INT;
DECLARE current_record CURSOR FOR SELECT id FROM A where b_id is null;
DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = TRUE;
OPEN current_record;
main_loop: LOOP
FETCH current_record INTO recordId;
IF done THEN
LEAVE main_loop;
END IF;
-- fetching some value from table b
select id into newValue from B where ...
-- setting new value in record
update A set b_id = newValue where id = recordId;
END LOOP;
END
答案是,如果游标没有返回任何行,而且如果表B上的select没有返回任何行,则不仅执行“找不到处理程序”。我的解决方案是使用由处理程序设置的第二个变量,并在select:
之后重置“done”变量 DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = TRUE, noBfound = TRUE;
[...]
select id into newValue from B where ...
IF (noBfound = TRUE) THEN
SET done = FALSE;
END IF;
[...]
补充:显然可以在没有第二个变量的情况下通过简单地重置选择后的“完成”:
DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = TRUE;
[...]
select id into newValue from B where ...
SET done = FALSE;
[...]
答案 1 :(得分:0)
您是否尝试过LOOP而不是REPEAT构造?似乎在MySQL中工作得更好。用以下代码将REPEAT替换为END REPEAT部分:
inv_loop: LOOP
FETCH cur1 INTO current_inventory_ID;
IF done = 1 THEN
LEAVE inv_loop;
END IF;
UPDATE _debug SET rows=rows+1;
END LOOP;
答案 2 :(得分:0)
IF done THEN
LEAVE main_loop;
ELSE
ITERATE main_loop;
END IF;