Question

我有动画gif和im使用类来解析它的图像（帧）。课程是：

using System;
using System.Drawing;
using System.Drawing.Imaging;
using System.Collections.Generic;
using System.IO;

public class AnimatedGif
{
    private List<AnimatedGifFrame> mImages = new List<AnimatedGifFrame>();
    public AnimatedGif(string path)
    {
        Image img = Image.FromFile(path);
        int frames = img.GetFrameCount(FrameDimension.Time);
        if (frames <= 1) throw new ArgumentException("Image not animated");
        byte[] times = img.GetPropertyItem(0x5100).Value;
        int frame = 0;
        for (; ; )
        {
            int dur = BitConverter.ToInt32(times, 4 * frame);
            mImages.Add(new AnimatedGifFrame(new Bitmap(img), dur));
            if (++frame >= frames) break;
            img.SelectActiveFrame(FrameDimension.Time, frame);
        }
        img.Dispose();
    }
    public List<AnimatedGifFrame> Images { get { return mImages; } }
}

public class AnimatedGifFrame
{
    private int mDuration;
    private Image mImage;
    internal AnimatedGifFrame(Image img, int duration)
    {
        mImage = img; mDuration = duration;
    }
    public Image Image { get { return mImage; } }
    public int Duration { get { return mDuration; } }
}

现在在form1中，我在这种情况下循环遍历帧4，我想以任何角度旋转动画。现在它每转45或90度。我想为动画添加更多帧（图像），所以如果我将旋转设置为31或10度，那么我将看到动画旋转10度。

这是Form1中的代码不能正常工作。我正在使用一个旋转功能，如果它没有任何工作，我还没有测试。

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;

namespace AnimatedGifEditor
{
    public partial class Form1 : Form
    {
        Image myImage;
        AnimatedGif myGif;
        Bitmap bitmap;

        public Form1()
        {
            InitializeComponent();

            myImage = Image.FromFile(@"D:\fananimation.gif");
            myGif = new AnimatedGif(@"D:\fananimation.gif");
            for (int i = 0; i < myGif.Images.Count; i++)
            {
                pictureBox1.Image = myGif.Images[3].Image;
                bitmap = new Bitmap(pictureBox1.Image);
                rotateImage(bitmap, 76);
                pictureBox1.Image = bitmap;
            }


        }

        private void Form1_Load(object sender, EventArgs e)
        {

        }



private Bitmap RotateImg(Bitmap bmp, float angle, Color bkColor)
    {
        int w = bmp.Width;
        int h = bmp.Height;
        bmp.PixelFormat pf = default(bmp.PixelFormat);
        if (bkColor == Color.Transparent)
        {
            pf = bmp.Format32bppArgb;
        }
        else
        {
            pf = bmp.PixelFormat;
        }

        Bitmap tempImg = new Bitmap(w, h, pf);
        Graphics g = Graphics.FromImage(tempImg);
        g.Clear(bkColor);
        g.DrawImageUnscaled(bmp, 1, 1);
        g.Dispose();

        GraphicsPath path = new GraphicsPath();
        path.AddRectangle(new RectangleF(0f, 0f, w, h));
        Matrix mtrx = new Matrix();
        //Using System.Drawing.Drawing2D.Matrix class 
        mtrx.Rotate(angle);
        RectangleF rct = path.GetBounds(mtrx);
        Bitmap newImg = new Bitmap(Convert.ToInt32(rct.Width), Convert.ToInt32(rct.Height), pf);
        g = Graphics.FromImage(newImg);
        g.Clear(bkColor);
        g.TranslateTransform(-rct.X, -rct.Y);
        g.RotateTransform(angle);
        g.InterpolationMode = InterpolationMode.HighQualityBilinear;
        g.DrawImageUnscaled(tempImg, 0, 0);
        g.Dispose();
        tempImg.Dispose();
        return newImg;
    }
    }
}

可以在此处找到用于测试的动画gif：

enter image description here

Answer 1

我不明白你的问题是什么，但我认为你的代码可以改进。我认为您不需要直接使用Matrix类。有一些功能可以帮助您。事实上，您唯一需要的是：将旋转点设置为中心，旋转图形并在其上绘制，使用Graphics类的某些函数。因此，要旋转图像，您可以使用以下简单代码：

private Bitmap RotateImage(Bitmap bmp, float angle) {
     Bitmap rotatedImage = new Bitmap(bmp.Width, bmp.Height);
     using (Graphics g = Graphics.FromImage(rotatedImage)) {
        // Set the rotation point to the center in the matrix
        g.TranslateTransform(bmp.Width / 2, bmp.Height / 2);
        // Rotate
        g.RotateTransform(angle);
        // Restore rotation point in the matrix
        g.TranslateTransform(- bmp.Width / 2, - bmp.Height / 2);
        // Draw the image on the bitmap
        g.DrawImage(bmp, new Point(0, 0));
     }

     return rotatedImage;
}

Answer 2

根据以前的答案，我创建了这个没有剪切图像的代码（其他示例对我不起作用）

    private Bitmap RotateImage(Bitmap bmp, float angle)
    {
        float height = bmp.Height;
        float width = bmp.Width;
        int hypotenuse = System.Convert.ToInt32(System.Math.Floor(Math.Sqrt(height * height + width * width)));
        Bitmap rotatedImage = new Bitmap(hypotenuse, hypotenuse);
        using (Graphics g = Graphics.FromImage(rotatedImage))
        {
            g.TranslateTransform((float)rotatedImage.Width / 2, (float)rotatedImage.Height / 2); //set the rotation point as the center into the matrix
            g.RotateTransform(angle); //rotate
            g.TranslateTransform(-(float)rotatedImage.Width / 2, -(float)rotatedImage.Height / 2); //restore rotation point into the matrix
            g.DrawImage(bmp, (hypotenuse - width) / 2, (hypotenuse - height) / 2, width, height);
        }
        return rotatedImage;
    }

Answer 3

你试过RotateFlip吗？

public partial class Form1 : Form
{
    Image myImage;
    AnimatedGif myGif;
    Bitmap bitmap;
    public Form1()
    {
        InitializeComponent();
        myImage = Image.FromFile(@"D:\fananimation.gif");
        bitmap = new Bitmap(myImage);
        bitmap.RotateFlip(System.Drawing.RotateFlipType.Rotate90FlipNone);
        this.pictureBox1.Image = bitmap;
    }

}

Source

Answer 4

我自己尝试了@Omar的答案，并意识到，原始图像在两侧被切割......我已经重写了它，因此它将图像调整为新尺寸：

private static Bitmap RotateImage(Bitmap bmp, float angle)
{
    float alpha = angle;

    //edit: negative angle +360
    while(alpha <0) alpha +=360;

    float gamma = 90;
    float beta = 180 - angle - gamma;

    float c1 = bmp.Height;
    float a1 = (float)(c1 * Math.Sin(alpha * Math.PI / 180) / Math.Sin(gamma * Math.PI / 180));
    float b1 = (float)(c1 * Math.Sin(beta * Math.PI / 180) / Math.Sin(gamma * Math.PI / 180));

    float c2 = bmp.Width;
    float a2 = (float)(c2 * Math.Sin(alpha * Math.PI / 180) / Math.Sin(gamma * Math.PI / 180));
    float b2 = (float)(c2 * Math.Sin(beta * Math.PI / 180) / Math.Sin(gamma * Math.PI / 180));

    int width = Convert.ToInt32(b2 + a1);
    int height = Convert.ToInt32(b1 + a2);

    Bitmap rotatedImage = new Bitmap(width, height);
    using (Graphics g = Graphics.FromImage(rotatedImage))
    {
        g.TranslateTransform(rotatedImage.Width / 2, rotatedImage.Height / 2); //set the rotation point as the center into the matrix
        g.RotateTransform(angle); //rotate
        g.TranslateTransform(-rotatedImage.Width / 2, -rotatedImage.Height / 2); //restore rotation point into the matrix
        g.DrawImage(bmp, new Point((width - bmp.Width) / 2, (height - bmp.Height) / 2)); //draw the image on the new bitmap
    }
    return rotatedImage;
}

Answer 5

我在VB中使用此功能：

    Public Function RotateImage(ByRef image As Image, ByVal angle As Single) As Drawing.Bitmap
    If image Is Nothing Then
        Throw New ArgumentNullException("image")
    End If

    Dim pi2 As Single = Math.PI / 2.0
    Dim oldWidth As Single = image.Width
    Dim oldHeight As Single = image.Height

    Dim theta As Single = angle * Math.PI / 180.0
    Dim locked_theta As Single = theta

    If locked_theta < 0.0 Then locked_theta += 2 * Math.PI

    Dim newWidth, newHeight As Single
    Dim nWidth, nHeight As Integer

    Dim adjacentTop, oppositeTop As Single
    Dim adjacentBottom, oppositeBottom As Single

    If (locked_theta >= 0.0 And locked_theta < pi2) Or _
    (locked_theta >= Math.PI And locked_theta < (Math.PI + pi2)) Then
        adjacentTop = Math.Abs(Math.Cos(locked_theta)) * oldWidth
        oppositeTop = Math.Abs(Math.Sin(locked_theta)) * oldWidth

        adjacentBottom = Math.Abs(Math.Cos(locked_theta)) * oldHeight
        oppositeBottom = Math.Abs(Math.Sin(locked_theta)) * oldHeight
    Else
        adjacentTop = Math.Abs(Math.Sin(locked_theta)) * oldHeight
        oppositeTop = Math.Abs(Math.Cos(locked_theta)) * oldHeight

        adjacentBottom = Math.Abs(Math.Sin(locked_theta)) * oldWidth
        oppositeBottom = Math.Abs(Math.Cos(locked_theta)) * oldWidth
    End If



    newWidth = adjacentTop + oppositeBottom
    newHeight = adjacentBottom + oppositeTop

    nWidth = Int(Math.Ceiling(newWidth))
    nHeight = Int(Math.Ceiling(newHeight))

    Dim rotatedBmp As New Drawing.Bitmap(nWidth, nHeight)

    Dim g As Graphics = Graphics.FromImage(rotatedBmp)

    Dim points(2) As Point

    If (locked_theta >= 0.0 And locked_theta < pi2) Then

        points(0) = New Point(Int(oppositeBottom), 0)
        points(1) = New Point(nWidth, Int(oppositeTop))
        points(2) = New Point(0, Int(adjacentBottom))

    ElseIf locked_theta >= pi2 And locked_theta < Math.PI Then

        points(0) = New Point(nWidth, Int(oppositeTop))
        points(1) = New Point(Int(adjacentTop), nHeight)
        points(2) = New Point(Int(oppositeBottom), 0)

    ElseIf locked_theta >= Math.PI And locked_theta < (Math.PI + pi2) Then

        points(0) = New Point(Int(adjacentTop), nHeight)
        points(1) = New Point(0, Int(adjacentBottom))
        points(2) = New Point(nWidth, Int(oppositeTop))

    Else

        points(0) = New Point(0, Int(adjacentBottom))
        points(1) = New Point(Int(oppositeBottom), 0)
        points(2) = New Point(Int(adjacentTop), nHeight)
    End If

    g.DrawImage(image, points)

    g.Dispose()
    image.Dispose()

    Return rotatedBmp

End Function

Answer 6

根据Timo的代码，我进行了一些改进，通过改进，可以成功地将负角度（最大-360°）作为参数提供

>>> print(res)

[{'name': 'brian', 'location': ['Brookings, OR', 'Medford, OR']}, {'name': 'tommy', 'location': ['Portland, OR', 'Medford, OR', 'Oklahoma City, OK']}]

如何旋转任何程度的图像？

6 个答案: