Question

当我向右移动目标并向上看它直到它走到-zaxis的180度并且决定走向另一个方向时它会看目标。

Matrix4x4 camera::GetViewMat()
{
    Matrix4x4 oRotate, oView;
    oView.SetIdentity();

    Vector3 lookAtDir = m_targetPosition - m_camPosition;
    Vector3 lookAtHorizontal = Vector3(lookAtDir.GetX(), 0.0f, lookAtDir.GetZ());
    lookAtHorizontal.Normalize();

    float angle = acosf(Vector3(0.0f, 0.0f, -1.0f).Dot(lookAtHorizontal));
    Quaternions horizontalOrient(angle, Vector3(0.0f, 1.0f, 0.0f));

    ori = horizontalOrient;
    ori.Conjugate();
    oRotate = ori.ToMatrix();

    Vector3 inverseTranslate = Vector3(-m_camPosition.GetX(), -m_camPosition.GetY(), -m_camPosition.GetZ());
    oRotate.Transform(inverseTranslate);

    oRotate.Set(0, 3, inverseTranslate.GetX());
    oRotate.Set(1, 3, inverseTranslate.GetY());
    oRotate.Set(2, 3, inverseTranslate.GetZ());
    oView = oRotate;

    return oView;
}

Answer 1

正如所承诺的那样，一些代码显示了我让相机随时观察太空中特定点的方式。

首先，我们需要一种从角度和轴构造四元数的方法，我碰巧在pastebin上有这个，角度输入是弧度：

http://pastebin.com/vLcx4Qqh

确保你没有输入轴（0,0,0），这没有任何意义。

现在是实际的更新方法，我们需要让四元数将相机从默认方向旋转到指向目标点。请注意，我刚刚写了这篇文章，它可能需要一些调试，可能需要一些优化，但这至少应该让你朝着正确的方向发展。

void camera::update()
{
    // First get the direction from the camera's position to the target point
    vec3 lookAtDir = m_targetPoint - m_position;

    // I'm going to divide the vector into two 'components', the Y axis rotation
    // and the Up/Down rotation, like a regular camera would work.

    // First to calculate the rotation around the Y axis, so we zero out the y
    // component:
    vec3 lookAtHorizontal = vec3(lookAtDir.x, 0.0f, lookAtDir.z).normalize();

    // Get the quaternion from 'default' direction to the horizontal direction
    // In this case, 'default' direction is along the -z axis, like most OpenGL
    // programs. Make sure the projection matrix works according to this.
    float angle = acos(vec3(0.0f, 0.0f, -1.0f).dot(lookAtHorizontal));
    quaternion horizontalOrient(angle, vec3(0.0f, 1.0f, 0.0f));

    // Since we already stripped the Y component, we can simply get the up/down
    // rotation from it as well.
    angle = acos(lookAtDir.normalize().dot(lookAtHorizontal));
    if(angle) horizontalOrient *= quaternion(angle, lookAtDir.cross(lookAtHorizontal));

    // ...
    m_orientation = horizontalOrient;
}

现在实际采取m_orientation和m_position并获取世界 - ＆gt;相机矩阵

// First inverse each element (-position and inverse the quaternion),
// the position is rotated since the position within a matrix is 'added' last
// to the output vector, so it needs to account for rotation of the space.
mat3 rotationMatrix = m_orientation.inverse().toMatrix();
vec3 inverseTranslate = rotationMatrix * -m_position; // Note the minus

mat4 matrix = mat3; // just means the matrix is expanded, the last entry (bottom right of the matrix) is a 1.0f like an identity matrix would be.

// This bit is row-major in my case, you just need to set the translation of the matrix.
matrix[3] = inverseTranslate.x;
matrix[7] = inverseTranslate.y;
matrix[11] = inverseTranslate.z;

编辑 我认为它应该是显而易见的，但为了完整性，.dot（）采用向量的点积，.cross（）采用交叉积，执行方法是向量A，方法的参数是向量B.

C ++ OpenGL Quaternion for Camera翻转它

1 个答案: