Android:开发在“后台”运行的应用程序,如何?

时间:2012-08-21 02:51:00

标签: android

我习惯开发独立的应用程序,你点击它们,运行它们,当你完成后,你就退出了。

我现在有兴趣处理应用程序的新类型(不确定这是否是正确的词),并且想知道我应该怎么做。我不确定要研究什么,并且非常感谢你的建议,以帮助我开球。我会告诉你我的想法。

我的应用需要在拨号器中执行特殊操作。当用户拨打号码并且正在通话中时,我希望用户能够按菜单键,并找到一个选项以滚动浏览所有联系人(股票应用程序或我自己的列表)我从存储在手机中的联系人中抓取,然后选择一个。选择后,该联系人的号码将被粘贴到拨号器中(请记住,在通话过程中)。

我当然不希望答案告诉我如何准确地做到这一点,我只需要一些指导,因为我以前从未写过这种性质的应用程序。最重要的是,甚至可以做我想做的事情吗?

谢谢。

3 个答案:

答案 0 :(得分:3)

您需要浏览Android ServiceIntentServiceService是一个应用程序组件,可以在后台执行长时间运行的操作,但不提供用户界面(UI)。

以下示例来自android博客,它是Service

的实现
public class HelloService extends Service {
  private Looper mServiceLooper;
  private ServiceHandler mServiceHandler;

  // Handler that receives messages from the thread
  private final class ServiceHandler extends Handler {
      public ServiceHandler(Looper looper) {
          super(looper);
      }
      @Override
      public void handleMessage(Message msg) {
          // Normally we would do some work here, like download a file.
          // For our sample, we just sleep for 5 seconds.
          long endTime = System.currentTimeMillis() + 5*1000;
          while (System.currentTimeMillis() < endTime) {
              synchronized (this) {
                  try {
                      wait(endTime - System.currentTimeMillis());
                  } catch (Exception e) {
                  }
              }
          }
          // Stop the service using the startId, so that we don't stop
          // the service in the middle of handling another job
          stopSelf(msg.arg1);
      }
  }

  @Override
  public void onCreate() {
    // Start up the thread running the service.  Note that we create a
    // separate thread because the service normally runs in the process's
    // main thread, which we don't want to block.  We also make it
    // background priority so CPU-intensive work will not disrupt our UI.
    HandlerThread thread = new HandlerThread("ServiceStartArguments",
            Process.THREAD_PRIORITY_BACKGROUND);
    thread.start();

    // Get the HandlerThread's Looper and use it for our Handler 
    mServiceLooper = thread.getLooper();
    mServiceHandler = new ServiceHandler(mServiceLooper);
  }

  @Override
  public int onStartCommand(Intent intent, int flags, int startId) {
      Toast.makeText(this, "service starting", Toast.LENGTH_SHORT).show();

      // For each start request, send a message to start a job and deliver the
      // start ID so we know which request we're stopping when we finish the job
      Message msg = mServiceHandler.obtainMessage();
      msg.arg1 = startId;
      mServiceHandler.sendMessage(msg);

      // If we get killed, after returning from here, restart
      return START_STICKY;
  }

  @Override
  public IBinder onBind(Intent intent) {
      // We don't provide binding, so return null
      return null;
  }

  @Override
  public void onDestroy() {
    Toast.makeText(this, "service done", Toast.LENGTH_SHORT).show(); 
  }
}

另一方面,使用IntentService可以实现同样的目的,Serviceshttps://stackoverflow.com/a/4353653/432903的基类,可以按需处理异步请求。

public class HelloIntentService extends IntentService {

  /** 
   * A constructor is required, and must call the super IntentService(String)
   * constructor with a name for the worker thread.
   */
  public HelloIntentService() {
      super("HelloIntentService");
  }

  /**
   * The IntentService calls this method from the default worker thread with
   * the intent that started the service. When this method returns, IntentService
   * stops the service, as appropriate.
   */
  @Override
  protected void onHandleIntent(Intent intent) {
      // Normally we would do some work here, like download a file.
      // For our sample, we just sleep for 5 seconds.
      long endTime = System.currentTimeMillis() + 5*1000;
      while (System.currentTimeMillis() < endTime) {
          synchronized (this) {
              try {
                  wait(endTime - System.currentTimeMillis());
              } catch (Exception e) {
              }
          }
      }
  }
}

您还可以浏览SO {{3}}

答案 1 :(得分:2)

如果您的应用主要不是用javascript / webview / phonegap编写的,那么您只需查看Service类即可。该课程和链接的文件告诉您需要知道的一切。

答案 2 :(得分:1)

也许你可以使用IntentFilter,这样你就可以在用户使用拨号器时获得系统通知。 你应该学习可以在android中的后台工作的服务组件。

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