修改链接文本,然后在Ruby with Mechanize中单击它们

时间:2012-08-23 18:06:54

标签: ruby mechanize

我设法用Mechanize填写表单并获取链接列表。 部分结果如下:

[
  #<Mechanize::Page::Link "View" "/cgi-bin/dcdev/forms/C00508200/800329/">,
  #<Mechanize::Page::Link "View" "/cgi-bin/dcdev/forms/C00487363/800634/">,
  #<Mechanize::Page::Link "View" "/cgi-bin/dcdev/forms/C00498097/800463/">
] 

我无法弄清楚下一步是什么。

  1. 我需要抓取的网页不是那些链接,而是在链接末尾有/sa/ALL,例如:/cgi-bin/dcdev/forms/C00508200/800329/sa/ALL。如何在每个链接的末尾添加sa/ALL
  2. 然后,如何点击每个更正的链接,并保存生成的页面?循环?

2 个答案:

答案 0 :(得分:1)

这是你钓鱼的方式......

require 'nokogiri'

doc = Nokogiri::HTML(<<EOT)
<html>
  <body>
    <a href="/cgi-bin/dcdev/forms/C00508200/800329/">
    <a href="/cgi-bin/dcdev/forms/C00487363/800634/">
    <a href="/cgi-bin/dcdev/forms/C00498097/800463/">
  </body>
</html>
EOT

hrefs = doc.search('a').map{ |a| a['href'] + '/sa/ALL' }

Mechanize在内部使用Nokogiri作为HTML解析器。您可以使用以下内容访问doc Mechanize:

require 'mechanize'

agent = Mechanize.new
page = agent.get('http://www.example.net')

证明我们正在处理Nokogiri文件:

page.parser.class # => Nokogiri::HTML::Document < Nokogiri::XML::Document

获取页面中的链接进行操作:

page.parser.search('a').map(&:to_html)

返回:

[
    [ 0] "<a href=\"/\"><img src=\"/_img/iana-logo-pageheader.png\" alt=\"Homepage\"></a>",
    [ 1] "<a href=\"/domains/\">Domains</a>",
    [ 2] "<a href=\"/numbers/\">Numbers</a>",
    [ 3] "<a href=\"/protocols/\">Protocols</a>",
    [ 4] "<a href=\"/about/\">About IANA</a>",
    [ 5] "<a href=\"/go/rfc2606\">RFC 2606</a>",
    [ 6] "<a href=\"/about/\">About</a>",
    [ 7] "<a href=\"/about/presentations/\">Presentations</a>",
    [ 8] "<a href=\"/about/performance/\">Performance</a>",
    [ 9] "<a href=\"/reports/\">Reports</a>",
    [10] "<a href=\"/domains/\">Domains</a>",
    [11] "<a href=\"/domains/root/\">Root Zone</a>",
    [12] "<a href=\"/domains/int/\">.INT</a>",
    [13] "<a href=\"/domains/arpa/\">.ARPA</a>",
    [14] "<a href=\"/domains/idn-tables/\">IDN Repository</a>",
    [15] "<a href=\"/protocols/\">Protocols</a>",
    [16] "<a href=\"/numbers/\">Number Resources</a>",
    [17] "<a href=\"/abuse/\">Abuse Information</a>",
    [18] "<a href=\"http://www.icann.org/\">Internet Corporation for Assigned Names and Numbers</a>",
    [19] "<a href=\"mailto:iana@iana.org?subject=General%20website%20feedback\">iana@iana.org</a>"
]

抓住并改变他们:

links = page.parser.search('a').map{ |a| a['href'] + 'sa/ALL' }
[
    [ 0] "/sa/ALL",
    [ 1] "/domains/sa/ALL",
    [ 2] "/numbers/sa/ALL",
    [ 3] "/protocols/sa/ALL",
    [ 4] "/about/sa/ALL",
    [ 5] "/go/rfc2606sa/ALL",
    [ 6] "/about/sa/ALL",
    [ 7] "/about/presentations/sa/ALL",
    [ 8] "/about/performance/sa/ALL",
    [ 9] "/reports/sa/ALL",
    [10] "/domains/sa/ALL",
    [11] "/domains/root/sa/ALL",
    [12] "/domains/int/sa/ALL",
    [13] "/domains/arpa/sa/ALL",
    [14] "/domains/idn-tables/sa/ALL",
    [15] "/protocols/sa/ALL",
    [16] "/numbers/sa/ALL",
    [17] "/abuse/sa/ALL",
    [18] "http://www.icann.org/sa/ALL",
    [19] "mailto:iana@iana.org?subject=General%20website%20feedbacksa/ALL"
]

您应该使用哪些链接来确定以及如何重新获取这些链接,这对您来说是一种练习。

答案 1 :(得分:0)

page.links.each do |link|
  agent.get(link.href + 'sa/ALL').save
end
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