Question

美好的一天，我正在使用ASIHTTPRequest，我在请求中遇到了西里尔字母的问题。

我有这个要求：

self.getUsersFromSearchRequest = [ASIHTTPRequest requestWithURL:[NSURL URLWithString:[NSString stringWithFormat:@"%@&text=%@&count=20", SEARCH_FOR_USER, searchBar.text]]];
[self.getUsersFromSearchRequest setDelegate:self];
[self.getUsersFromSearchRequest startAsynchronous];

在此之后我有 requestFinished：和 requestFailed：方法：

    - (void)requestFinished:(ASIHTTPRequest *)request {
    self.dictionary = [NSJSONSerialization JSONObjectWithData:[request responseData] options:NSJSONWritingPrettyPrinted error:nil];

    if([request isEqual:self.getUsersFromSearchRequest]) {
        if ([[self.dictionary objectForKey:@"response"]  isKindOfClass:[NSArray class]]) {

            self.resultSearchUser = [self.dictionary objectForKey:@"response"];
            [self.searchDisplayController.searchResultsTableView reloadData];
        }
        self.searchResultsTable.hidden = NO;
        [MBProgressHUD hideHUDForView:self.view animated:YES];
    }
}

- (void)requestFailed:(ASIHTTPRequest *)request {
    UIAlertView *alertView = [[UIAlertView alloc]initWithTitle:NSLocalizedString(@"Internet Connection Error Alert Title", @"This is the Internet Connection Error Alert Title") message:NSLocalizedString(@"Internet Connection Error Alert Message Text", @"This is the Internet Connection Error Alert Message Text") delegate:nil cancelButtonTitle:NSLocalizedString(@"Internet Connection Error Alert Cancel Button Title", @"This is the Internet Connection Error Alert Cancel Button Title") otherButtonTitles:nil];
    [alertView show];
}

当我在搜索文本字段中输入拉丁字母时，一切都很顺利，但在我输入西里尔字母后，我立即进入 requestFailed：。有什么问题？

提前致谢！

Answer 1

问题解决了！您必须对URL字符串进行编码！像这样：

self.getUsersFromSearchRequest = [ASIHTTPRequest requestWithURL:[NSURL URLWithString:[[NSString stringWithFormat:@"%@&text=%@&count=20", SEARCH_FOR_USER, searchBar.text] stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]]];

ASIHTTPRequest和西里尔字母

1 个答案: