类型参数声明必须是标识符而不是类型

时间:2012-08-28 10:29:22

标签: c# generics

public abstract class BaseDocumentLayer : IDocumentLayer
{                                                       
   public IDocumentLayer NextLayer { get;set;}

   public virtual Document<T, U> ProcessDocument<T, U>(Document<T, U> document) {
      if(NextLayer != null)
         document = NextLayer.ProcessDocument(document);
      return document;          
   }
}

public override Document<GenericDatabaseDTO, GenericDatabaseConstants.ActionType> ProcessDocument<GenericDatabaseDTO, GenericDatabaseConstants.ActionType>(Document<GenericDatabaseDTO, GenericDatabaseConstants.ActionType> document)
{       
    return base.ProcessDocument<GenericDatabaseDTO, 
}

public static class GenericDatabaseConstants 
{    
    public enum ActionType 
    {                
       CreateGeneric,
       ReadGeneric,
       UpdateGeneric,
       DeleteGeneric,               
    }
}

为什么我会收到错误:类型参数声明必须是标识符而不是类型?

enter image description here

ERROR1:

public override Document<GenericDatabaseDTO, GenericDatabaseConstants.ActionType> ProcessDocument(Document<GenericDatabaseDTO, GenericDatabaseConstants.ActionType> document)
{   

    return base.ProcessDocument(document);
}

错误1'GenericDocumentLayer2.Document.GenericDatabase.ProcessLayer.ProcessDocument(GenericDocumentLayer2.TypeDefinition.Document)':找不到合适的方法来覆盖

我没有更改我的原始BaseLayer.ProcessDocument方法

更新

public void Add(GenericDatabaseField field) {
            var dto = new GenericDatabaseDTO();
            dto.Field = field;
            dto.Id = "test";

            var document = new Document<GenericDatabaseDTO, GenericDatabaseConstants.ActionType>(dto, GenericDatabaseConstants.ActionType.CreateGeneric, null);
            IDocumentLayer layer = DocumentFactory.CreateDocumentLayers();
                                          // The generic ProcessDocument is never called just the base version
        document = layer.ProcessDocument<GenericDatabaseDTO, GenericDatabaseConstants.ActionType>(document);                
    }

1 个答案:

答案 0 :(得分:1)

您无法覆盖特定类型的通用方法。这可以使用C ++的模板,但不能使用C#的泛型。

要编译代码,请将其更改为:

public override Document<TDTO, TActionType> ProcessDocument<TDTO, TActionType>(Document<TDTO, TActionType> document) 

这将编译,但它将覆盖所有泛型参数的基本类型方法。

如果要为一种类型提供特殊实现,可以添加非泛型重载,并在特殊处理后内部调用泛型版本:

public Document<GenericDatabaseDTO, GenericDatabaseConstants.ActionType> ProcessDocument(Document<GenericDatabaseDTO, GenericDatabaseConstants.ActionType> document)  
{
    // some special handling for this special case here...

    return base.ProcessDocument(document);
}

但是,请注意,这将在像这样的多态方案中打破:

假设上述方法在Derived中实施。 Derived源自Base

GenericDatabaseDTO dto = /*...*/;
GenericDatabaseConstants.ActionType actionType = /*...*/;

Derived d = new Derived();
Base b = d;

// calls the non-generic version with special handling from Derived:
d.ProcessDocument(dto, actionType);
// calls the generic version from Base:
b.ProcessDocument(dto, actionType);
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