嗨,我是php的新手可以请一些帮助。我正在创建一个网站,它有一个菜单,我需要它,以便如果点击像“link1”这样的链接,page1.php将加载到mainSection div中,如果点击了link2,则page2.php将加载到mainSection等中。所有页面:page1,page2,page3等将根据点击的链接加载到此单页中。这可能我不知道从哪里开始。感谢
<body>
<?php
<ul>
<li><a href="#" name="link1">link 1</a></li>
<li><a href="#" name="link2">link 2</a></li>
<li><a href="#" name="link3">link 3</a></li>
<li><a href="#" name="link4">link 4</a></li>
</ul>
?>
<div id="mainSection">
<?php
if (link1 == true){
include 'page1.php';
}
if (link2 == true){
include 'page2.php';
}
if (link3 == true){
include 'page3.php';
}
if (link4 == true){
include 'page4.php';
}
?>
</div>
</body>
答案 0 :(得分:2)
这是你可以从
开始的<body>
<ul>
<li><a href="?link=1" name="link1">link 1</a></li>
<li><a href="?link=2" name="link2">link 2</a></li>
<li><a href="?link=3" name="link3">link 3</a></li>
<li><a href="?link=4" name="link4">link 4</a></li>
</ul>
<div id="mainSection">
<?php
$link=$_GET['link'];
if ($link == '1'){
include 'page1.php';
}
if ($link == '2'){
include 'page2.php';
}
if ($link == '3'){
include 'page3.php';
}
if ($link == '4'){
include 'page4.php';
}
?>
</div>
</body>
答案 1 :(得分:2)
除了majid的代码,您还必须检查链接是否已设置,否则会引发未定义$ link的错误。
<div id="mainSection">
<?php
if(isset($_GET['link'])){
$link=$_GET['link'];
if ($link == '1'){
include 'page1.php';
}
if ($link == '2'){
include 'page2.php';
}
if ($link == '3'){
include 'page3.php';
}
if ($link == '4'){
include 'page4.php';
}
} ?>
</div>
</body>
答案 2 :(得分:1)
将链接的格式更改为:
<a href="/?1" name="link1">link 1</a>...
然后将PHP更改为:
<?php
if ($_SERVER['QUERY_STRING'] == 1){
include 'page1.php';
}
if ($_SERVER['QUERY_STRING'] == 2){
include 'page2.php';
}
if ($_SERVER['QUERY_STRING'] == 3){
include 'page3.php';
}
if ($_SERVER['QUERY_STRING'] == 4){
include 'page4.php';
}
?>