Question

我在使用此脚本进行表单验证方面遇到了一些问题，最初使用JavaScript然后再次验证，然后使用PHP进行提交。谁能在这里看到这个问题？我打开文件时看不到任何内容。我是PHP的新手。忽略表格格式。这是一本书中的实验室，所以重点是PHP＆amp; JavaScript的。我知道CSS布局等。

非常感谢任何帮助。提前致谢

<?php

error_reporting(~0); ini_set('display_errors', 1);

//PHP adduser.php

//Start with the PHP code

$forename=$surname=$password=$age=$email="";

if(isset($_POST['forename']))
$forename = fix_string($_POST['forename']);
if(isset($_POST['surname']))
$surname = fix_string($_POST['surname']);
if(isset($_POST['password']))
$password = fix_string($_POST['password']);
if(isset($_POST['age']))
$age = fix_string($_POST['age']);
if(isset($_POST['email']))
$email = fix_string($_POST['email']);

$fail= validate_forename($forename);
$fail.= validate_surname($surname);
$fail.= validate_password($password);
$fail.= validate_age($age);
$fail.= validate_email($email);

echo "<html><head><title>An example form</title></head><body>";

if($fail==""){
  echo "Form data successfully validated: $forename,
  $surname, $password, $age, $email";        
}



//This is where you'd enter post fields to the DB
exit;

//Now the HTML & JavaScript goes here

回波＆LT;＆LT;＆LT; _SOQ

<style type="text/css">.signup{
  border:1px solid #999999;
  font:normal 14px helvetica;
  color:#444444;
  }
</style>


 <script type="text/javascript">

   function validate(form){

    fail = validateForename(form.forename.value);
    fail += validateSurname(form.surname.value);
    fail += validatePassword(form.password.value);
    fail += validateAge(form.age.value);
    fail += validateEmail(form.email.value);

      if(fail=="") return true;
      else alert(fail); return false;

    }

</script>

</head>
    <body>
      <table class="signup" border="0" cellpadding="2" cellspacing="5" 
       bgcolor="#eeeeee">
        <th colspan="2" align="center">Sign up form</th>

  <tr>
    <td colspan="2">Sorry, the following errors were found<br/>
     in your form: <i>$fail</i>
    </td>
  </tr>


<form method="post" action="adduser.php" onsubmit="validate(this.form)">

<tr><td>Forename:</td><td><input type="text" maxlength="32"
  name="forename" value="$forename"/></td>
</tr>

<tr><td>Surname:</td><td><input type="text" maxlength="32"
  name="surname" value="$surname"/></td>
</tr>

<tr><td>Password:</td><td><input type="text" maxlength="32"
  name="password" value="$password"/></td>
</tr>

<tr><td>Age:</td><td><input type="text" maxlength="32"
  name="age" value="$age"/></td>
</tr>

<tr><td>Email:</td><td><input type="text" maxlength="32"
  name="email" value="$email"/></td>
</tr>

<tr><td colspan="2" align="center">
   <input type="submit" value="Sign-up"/></td>
</tr>

  </form>
</table>

<script type="text/javascript">

function validateForename(field){
  if(field=="") return "No surname was entered";
  return "";
}

function validateSurname(field){
  if(field=="") return "No surname was entered";
  return "";
}

function validatePassword(field){
   if(field=="") return "No surname was entered";
   else if(field.length<6) return "Passwords, must be at least 6 characters";
   else if([^/a-zA-Z0-9_-/]) return "Only a-zA-Z0-9_- characters are allowed ";
   return "";
 }

function validateAge(field){
   if((field=="") || (isNaN(field)) return "No age was entered";
   else if((field<18) || (field>101))  return "Age must be between 18 and 101 years";
   else if(/[^a-zA-Z0-9_-]/.test(field)) 
   return "Only a-zA-Z0-9_- characters are allowed ";
   return "";
 }

 function validateEmail(field){
   if(field=="") return "No surname was entered";
   else if(!((field.indexOf('@')>0) && (field.indexOf('.')>0)) ||
   /[^a-zA-Z0-9-]/.test(field)) return "E-mail address invalid";
   return "";
 }

</script>

  </body>
</html>

_SOQ;

//最后是PHP函数

function validate_forename($field){
  if($field=="") return "No forename was entered";
  return "";
}

function validate_surname($field){
  if($field=="") return "No surname was entered";
  return "";
}

function validate_password($field){
  if($field=="") return "No password was entered";
  elseif(strlen($field) <6) return "Passwords, must be at least 6 characters";
  elseif(!preg_match("/[^a-zA-Z0-9_-]/", $field)) 
  return "Only a-zA-Z0-9_- characters are allowed ";
  return "";
}

function validate_age($field){
  if($field<18 || field>101) return "Age must be between 18 and 101 years";
  return "";
}

function validate_email($field){
  if($field=="") return "No surname was entered";
  elseif(!(strpos($field, ".")>0) && 
         (strpos($field, "@")>0) ||
          preg_match("/[^a-zA-Z0-9_]/",$field)) 
        return "E-mail address invalid";
        return "";
}

//sanitise the PHP input

function fix_string($string){
  if(get_magic_quotes_gpc($string)) stripslashes($string);
  return htmlentities($string);

 }

＆GT;

Answer 1

如果你什么都没看到，你就有一个php错误

转到php.ini并将错误报告设置为E_ALL并将错误显示为on 或

<?php
     error_reporting(E_ALL);
     ini_set("display_errors", 1);
?>

Answer 2

if($fail=""){

您指定而不是检查是否相等。然后，由于分配的值为false，因此永远不会执行相应的成功代码。

Answer 3

当您真正想要$fail=""时，看起来您正在使用$fail==""。第一个是赋值表达式，第二个是==是一个比较表达式。您的使用情况将始终解析为false（通过您刚设置的空字符串），无论之前设置的$fail是什么，因为您只是重置它：

$fail = "hello";
var_dump($fail); //string(5) "hello"
var_dump($fail=""); //string(0) ""
var_dump(""); //string(0) ""

所以你的if语句就变成了

if("") {
    //never get here
} else {
    //always get here, but you have nothing defined
}

PHP及其问题JavaScript表单验证脚本

3 个答案: