Question

现在我正在尝试使用Android 3.0（API 11）ECLIPSE进行另一个弹出项目。但我得到了错误。无法实例化类型PopupMenu.OnMenuItemClickListener MainActivity.java

＆安培;

PopupMenu类型中的方法getMenuInflater（）不适用于参数（int，Object）MainActivity.java）
任何帮助将不胜感激。感谢。

package com.example.indicationsss;

import android.os.Bundle;
import android.app.Activity;
import android.view.Menu;
import android.view.MenuItem;
import android.view.View;
import android.widget.PopupMenu;
import android.widget.Toast;

public class MainActivity extends Activity {

     @Override
     public void onCreate(Bundle savedInstanceState) {
          super.onCreate(savedInstanceState);
          setContentView(R.layout.activity_main);
     }

     public void onPopupBtClick (View view) {
          PopupMenu menu = new PopupMenu(this, view);
      menu.getMenuInflater().inflate(R.menu.activity_main, menu.getMenu());
      menu.setOnMenuItemClickListener(**new PopupMenu.OnMenuItemClickListener**());
     }

     public boolean onMenuItemClick(MenuItem item) {
          Toast toast = Toast.makeText (MainActivity.this,
            item.getTitle() + "was pressed",
            Toast.LENGTH_SHORT);
          toast.show();
          return true;
     }
}

Answer 1

在onPopupBtClick（）中，声明自己的popupListener接口，如下所示：menu.setOnMenuItemClickListener(popupListener );

然后在活动的其他地方（但在onPopupBtClick（）之外），实现接口：

private PopupMenu.OnMenuItemClickListener popupListener = new PopupMenu.OnMenuItemClickListener() {
                  @Override
                  public boolean onMenuItemClick(MenuItem item) {
                     // etc., etc., 
                     ....
                  }
    }

无法实例化PopupMenu.OnMenuItemClickListener类型

1 个答案: