我查看Post。但我仍然不明白逻辑错误是什么。我仍然收到此错误。我试图转储模拟器流量。但我仍然无法解决问题所在。
从流量转储中，这是Android作为请求发送到服务器的内容。您也可以看到响应：
GET /Authenticate/ HTTP/1.1
Authorization: Basic asdfasdfasdfas
Accept-Charset: UTF-8
Host: www.domain.com
User-Agent: Dalvik/1.4.0 (Linux; U; Android 2.3.3; sdk Build/GRI34)
Connection: Keep-Alive
Accept-Encoding: gzip
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PÙ[ ˜ároP"8«‹ HTTP/1.1 400 Bad Request
Date: Thu, 13 Sep 2012 04:47:42 GMT
Server: Apache/2.2.15 (CentOS)
Content-Length: 310
Connection: close
Content-Type: text/html; charset=iso-8859-1
<!DOCTYPE HTML PUBLIC "-//IETF//DTD HTML 2.0//EN">
<html><head>
<title>400 Bad Request</title>
</head><body>
<h1>Bad Request</h1>
<p>Your browser sent a request that this server could not understand.<br />
</p>
<hr>
<address>Apache/2.2.15 (CentOS) Server at www.domain.com Port 80</address>
</body></html>
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text/html; charset=iso-8859-1Bad Request
我不知道这些额外字符是什么意思。但我试图从中找出问题。
这是基本代码：
String credentials = username + ":" + password;
byte[] toencode = null;
try {
toencode = credentials.getBytes("UTF-8");
} catch (UnsupportedEncodingException e1) {
e1.printStackTrace();
}
HttpURLConnection conn = null;
try {
//Utilities.isNetworkAvailable(context);
URL url = new URL(params[0]);
Log.d(params[0],"UR");
conn = (HttpURLConnection) url.openConnection();
conn.setRequestProperty("Authorization", "Basic " + Base64.encodeToString(toencode, Base64.DEFAULT));
conn.setRequestProperty("Accept-Charset", "UTF-8");
conn.setRequestProperty("Host", "www.domain.com");
conn.setRequestMethod("GET");
conn.setDoOutput(true);
String data = conn.getInputStream().toString();
return data;
}
有什么想法吗？
更新
我检查了Web服务器日志以查看请求是否正在访问服务器以及请求是否有任何问题。这是我从错误日志中看到的：
[Thu Sep 13 10:05:24 2012] [error] [client 91.222.195.132] client sent HTTP/1.1 request without hostname (see RFC2616 section 14.23): /Authenticate/
[Thu Sep 13 23:11:57 2012] [error] [client 91.222.195.132] client sent HTTP/1.1 request without hostname (see RFC2616 section 14.23): /Authenticate/
[Thu Sep 13 23:12:03 2012] [error] [client 91.222.195.132] client sent HTTP/1.1 request without hostname (see RFC2616 section 14.23): /Authenticate/
但是我正在设置请求的标头属性。
有什么想法吗？
答案 0 :(得分：2)
我自己想出来了。它是设置标题顺序的问题。
编辑：我使用过的订单。
URL url = new URL(strUrl);
conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("GET");
conn.setRequestProperty("Host", "myhost.com");
conn.setRequestProperty("Authorization", "Basic " + Base64.encodeToString(toencode, Base64.DEFAULT));
conn.setRequestProperty("User-Agent", "Mozilla/5.0 (Macintosh; U; PPC; en-US; rv:1.3.1)");
conn.setRequestProperty("Accept-Charset", "UTF-8");
conn.setConnectTimeout (5000) ;
conn.setDoOutput(true);
conn.setDoInput(true);
答案 1 :(得分：1)
我也遇到了这个问题，但是我通过更改代码来解决它，现在我正在使用以下代码行
BufferedReader reader;
StringBuffer buffer;
String res = null;
try {
URL url = new URL(request_url);
HttpURLConnection con = (HttpURLConnection) url.openConnection();
con.setReadTimeout(40000);
con.setConnectTimeout(40000);
con.setRequestMethod("GET");
con.setRequestProperty("Accept","application/json");
con.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
con.setDoInput(true);
con.setDoOutput(true);
int status = con.getResponseCode();
InputStream inputStream;
if (status == HttpURLConnection.HTTP_OK) {
inputStream = con.getInputStream();
} else {
inputStream = con.getErrorStream();
}
reader = new BufferedReader(new InputStreamReader(inputStream));
buffer = new StringBuffer();
String line = "";
while ((line = reader.readLine()) != null) {
buffer.append(line);
}
res = buffer.toString();
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (ProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return res;
答案 2 :(得分：0)
试试这个
static final String _url = "http://www.google.com";
static final String charset = "UTF-8";
// to build the query string that will send the message
private static String buildRequestString(String param1,
String param2, String param3, String param4, String param5)
throws UnsupportedEncodingException {
String[] params = new String[5]; //customize this as per your need
params[0] = param1;
params[1] = param2;
params[2] = param3;
params[3] = param4;
params[4] = param5;
String query = String.format(
"uid=%s&pwd=%s&msg=%s&phone=%s&provider=%s",
URLEncoder.encode(params[0], charset),
URLEncoder.encode(params[1], charset),
URLEncoder.encode(params[2], charset),
URLEncoder.encode(params[3], charset),
URLEncoder.encode(params[4], charset));
return query;
}
public static void doSomething(String param1, String param2,
String param3, String param4, String param5) throws Exception {
// To establish the connection and perform the post request
URLConnection connection = new URL(_url
+ "?"
+ buildRequestString(param1, param2, param3, param4,
param5)).openConnection();
connection.setRequestProperty("Accept-Charset", charset);
// This automatically fires the request and we can use it to determine
// the response status
InputStream response = connection.getInputStream();
BufferedReader br = new BufferedReader(new InputStreamReader(response));
// This stores the response code.
// Any call to br.readLine() after this is null.
responsecode = br.readLine();
// And this logs the already stored response code
Log.d("ServerResponse", responsecode);
responseInt = Integer.valueOf(responsecode).intValue();
}