Question

如何在C＃中初始化数组？

Answer 1

像这样：

int[] values = new int[] { 1, 2, 3 };

或者这个：

int[] values = new int[3];
values[0] = 1;
values[1] = 2;
values[2] = 3;

Answer 2

var array = new[] { item1, item2 }; // C# 3.0 and above.

Answer 3

阅读本文

http://msdn.microsoft.com/en-us/library/aa288453%28VS.71%29.aspx

//can be any length
int[] example1 = new int[]{ 1, 2, 3 };

//must have length of two
int[] example2 = new int[2]{1, 2};           

//multi-dimensional variable length
int[,] example3 = new int[,]{ { 1, 2, 3 }, { 4, 5, 6 } };


//multi-dimensional fixed length
int[,] example4 = new int[1,2] { { 1, 2} };

//array of array (jagged)
int[][] example5 = new int[5][];

Answer 4

char[] charArray = new char[10];

如果您使用的是C＃3.0或更高版本，并且您正在初始化十进制中的值，则可以省略类型（，因为它是推断的）

var charArray2 = new [] {'a', 'b', 'c'};

Answer 5

int [ ] newArray = new int [ ] { 1 , 2 , 3 } ;

Answer 6

string[] array = new string[] { "a", "b", "c" };

如何在C＃中初始化数组？

6 个答案: