Question

请在下面找到实体代码，

@Entity
public class A implements Serializable {

    @Id
    @GeneratedValue(strategy=GenerationType.AUTO)
    private Long id;

    @OneToMany(cascade={CascadeType.PERSIST, CascadeType.MERGE}, fetch = FetchType.LAZY, mappedBy="parentActivity")        
    private Set<A> subActivities;

    @ManyToOne(cascade = CascadeType.REFRESH, fetch = FetchType.LAZY)
    @JoinColumn(name = "PARENTACTIVITYID", insertable = true, updatable = true)
    private A parentActivity;

    // Getters, Setters, serialVersionUID, etc...
}

如果我们想要同时保持父母和孩子，那么下面的代码可以完美地运行

public static void main(String[] args) {

    EntityManager em = ... // from EntityManagerFactory, injection, etc.

    em.getTransaction().begin();

    A parentActivuty   = new A();
    A subActivity1      = new A();
    A subActivity2 = new A();

    son.setParentActivity(parent);
    daughter.setParentActivity(parent);
    parent.setSubActivity(Arrays.asList(subActivity1, subActivity2));

    em.persist(parent);
    em.persist(son);
    em.persist(daughter);

    em.getTransaction().commit();
}

但是在这种情况下，我在数据库中有父对象，并希望持久保存子对象可能的解决方案......？

Answer 1

您从数据库中获取父级，执行附件并保留两个孩子：

A parent = em.get(A.class, parentId);
A son = new A();
A daughter = new A();
son.setParentActivity(parent);
daughter.setParentActivity(parent);
em.persist(son);
em.persist(daughter);
parent.getSubActivities().add(son);
parent.getSubActivities().add(daughter);

与同一实体的一对多关系

1 个答案: