Question

我需要从文本文件中删除punc。

文本文件是这样的

ffff，hhhh，＆amp; tommorw home，
你离开了吗？

我正在尝试

PUNC =（”。？，/;'＆安培; - “）

f = open（'file.txt'，'r'）
for line in f:
    strp=line.replace(punc,"")
    print(strp)

我需要输出：

ffff hhhh tommorw home
Have you from gone

这是返回每一行，但是punc仍在那里＆gt;可以使用一些帮助。谢谢

Answer 1

使用str.translate删除字符串中的字符。

在Python 2.x中：

# first arg is translation table, second arg is characters to delete
strp = line.translate(None, punc)

在Python 3中：

# translation table maps code points to replacements, or None to delete
transtable = {ord(c): None for c in punc}
strp = line.translate(transtable)

或者，您可以使用str.maketrans构建transtable：

# first and second arg are matching translated values, third arg (optional) is the characters to delete
transtable = str.maketrans('', '', punc)
strp = line.translate(transtable)

Answer 2

>>> import string
>>> with open('/tmp/spam.txt') as f:
...   for line in f:
...     words = [x.strip(string.punctuation) for x in line.split()]
...     print ' '.join(w for w in words if w)
... 
ffff hhhh tommorw home
Have you from gone

Answer 3

import string

str_link = open('replace.txt','r').read()

#str_link = "ffff, hhhh, & tommorow home, Have you from gone?"

punc = list(",./;'?&-")

for line in str_link:
    if line in punc:
        str_link = str_link.replace(line,"") 

print str_link

Answer 4

我认为使用str.translate的想法很棒，但这是另一种方法：

punc=set(",./;'?&-")

for line in f:
    strp=''.join(c for c in line if not c in punc)
    print(strp)

Python - 从列表中删除标点符号

4 个答案: