使用c#如何读取xml文件

时间:2012-09-17 07:44:49

标签: c# xml xml-parsing

<Reports>
  <Databases>
    <Database>Axxest</Database>
    <Database>Axxest2</Database>
  </Databases>
</Reports>

如何阅读AxxestAxxest2使用c#来读取这样的xml文件?

我试试这个:

XmlDocument xld = new XmlDocument();
xld.Load(XmlPath);
XmlNodeList xnl = xld.SelectSingleNode("Reports").ChildNodes;
tableList.Clear();
foreach (XmlNode xn in xnl)
{
    tableList.Add(xn.InnerText);
} 

但有些不对劲?

3 个答案:

答案 0 :(得分:1)

尝试SelectNodes方法和XPath

XmlDocument xld = new XmlDocument();
xld.Load(XmlPath);
XmlNodeList xnl = xld.SelectNodes("Reports/Databases/Database");
foreach (XmlNode xn in xnl)
{
    tableList.Add(xn.InnerText);
}

答案 1 :(得分:0)

请参阅Documentation's Example

StringBuilder output = new StringBuilder();

String xmlString =
        @"<?xml version='1.0'?>
        <!-- This is a sample XML document -->
        <Items>
          <Item>test with a child element <more/> stuff</Item>
        </Items>";
// Create an XmlReader
using (XmlReader reader = XmlReader.Create(new StringReader(xmlString)))
{
    XmlWriterSettings ws = new XmlWriterSettings();
    ws.Indent = true;
    using (XmlWriter writer = XmlWriter.Create(output, ws))
    {

        // Parse the file and display each of the nodes.
        while (reader.Read())
        {
            switch (reader.NodeType)
            {
                case XmlNodeType.Element:
                    writer.WriteStartElement(reader.Name);
                    break;
                case XmlNodeType.Text:
                    writer.WriteString(reader.Value);
                    break;
                case XmlNodeType.XmlDeclaration:
                case XmlNodeType.ProcessingInstruction:
                    writer.WriteProcessingInstruction(reader.Name, reader.Value);
                    break;
                case XmlNodeType.Comment:
                    writer.WriteComment(reader.Value);
                    break;
                case XmlNodeType.EndElement:
                    writer.WriteFullEndElement();
                    break;
            }
        }

    }
}
OutputTextBlock.Text = output.ToString();

答案 2 :(得分:0)

如果要在xml文件中找到一些节点,可以使用XPath进行查询,这就是w3 schools中所需的全部内容。

如果调试代码,可以发现xnl的计数是1,它只包含“Databases”节点。 “SelectSingleNode”表示选择一个节点,在您的代码中,首先选择“Reports”,然后返回其子节点,该子节点仅包含“数据库”。您可以尝试使用Ria的代码,使用SelectNodes而不是SelectSingleNode。但你仍然可以使用“SelectSingleNode”,试试这个:

XmlNodeList xnl = xld.SelectSingleNode("Reports/Databases").ChildNodes;  

希望它对你有所帮助。

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