Question

我正在试图弄清楚如何使用PHP重命名XML节点？

我到目前为止：

$dom = new DOMDocument( '1.0' );
$dom->preserveWhiteSpace = false;
$dom->formatOutput = true;

// load the xml file
$dom->loadXML( '<?xml version="1.0" encoding="ISO-8859-1"?>
<library>
  <data>
    <invite>
      <username>jmansa</username>
      <userid>1</userid>
    </invite>
    <update>1</update>
  </data>
</library>', LIBXML_NOBLANKS );
$xpath = new DOMXPath($dom);

//find all 'data' nodes.
$node = $xpath->query("//data");

// if found
if( $node->length ) {
    foreach ($node as $n) {
       // RENAME HERE? //
    }
}

echo "<xmp>". $dom->saveXML() ."</xmp>";

现在，我想将<data>重命名为<invites>。可以这样做，如果是，怎么做？

Answer 1

无法通过DOM重命名节点的名称（分别为“数据”或“邀请”），因为Node::nodeName property is read-only。

您可以创建一个名为“invites”的新节点，将其附加到“data”节点之前，将“data”的子节点移动到新的“invites”节点，删除“data”节点，然后输出树得到你的结果。

示例：

<?php // Create a test document. $dom = new DOMDocument( '1.0' ); $dom->preserveWhiteSpace = false; $dom->formatOutput = true; // Load the xml file. $dom->loadXML('<?xml version="1.0" encoding="ISO-8859-1"?'.'> <library> <data attr1="1" attr2="2"> <invite> <username>jmansa</username> <userid>1</userid> </invite> <update>1</update> </data> </library>', LIBXML_NOBLANKS ); $xpath = new DOMXPath($dom); // Convert <data> to <invites>. if ($dataNode = $xpath->query("/library/data")->item(0)) { // Create the <invites> node. $invitesNode = $dom->createElement('invites'); $dataAttrs = $dataNode->attributes; foreach ($dataAttrs as $dataAttr) { $invitesNode->setAttributeNodeNS($dataAttr->cloneNode()); } $dom->documentElement->appendChild($invitesNode); // Move the <data> children over. if ($childNodes = $xpath->query("/library/data/*")) { foreach ($childNodes as $childNode) { $invitesNode->appendChild($childNode); } } // Remove <data>. $dataNode->parentNode->removeChild($dataNode); } // Test the result. echo $dom->saveXML(); ?>

Answer 2

我的解决方案，扩展测试用例：

// Changes the name of element $element to $newName.
function renameElement($element, $newName) {
  $newElement = $element->ownerDocument->createElement($newName);
  $parentElement = $element->parentNode;
  $parentElement->insertBefore($newElement, $element);

  $childNodes = $element->childNodes;
  while ($childNodes->length > 0) {
    $newElement->appendChild($childNodes->item(0));
  }

  $attributes = $element->attributes;
  while ($attributes->length > 0) {
    $attribute = $attributes->item(0);
    if (!is_null($attribute->namespaceURI)) {
      $newElement->setAttributeNS('http://www.w3.org/2000/xmlns/',
                                  'xmlns:'.$attribute->prefix,
                                  $attribute->namespaceURI);
    }
    $newElement->setAttributeNode($attribute);
  }

  $parentElement->removeChild($element);
}

function prettyPrint($d) {
  $d->formatOutput = true;
  echo '<pre>'.htmlspecialchars($d->saveXML()).'</pre>';
}

$d = new DOMDocument( '1.0' );
$d->loadXML('<?xml version="1.0"?>
<library>
  <data a:foo="1" x="bar" xmlns:a="http://example.com/a">
    <invite>
      <username>jmansa</username>
      <userid>1</userid>
    </invite>
    <update>1</update>
  </data>
</library>');

$xpath = new DOMXPath($d);
$elements = $xpath->query('/library/data');
if ($elements->length == 1) {
  $element = $elements->item(0);
  renameElement($element, 'invites');
}

prettyPrint($d);

顺便说一句，我将此解决方案作为comment添加到DOMElement的PHP文档中。

使用PHP重命名XML节点

2 个答案: