Question

在下面的代码中，我需要知道在引发事件时传递两个字符串的语法。

 [PublishEvent("Click")]
 public event EventHandler<EventArgs<string>> MyEvent;

谢谢，撒克逊。

Answer 1

最干净的方法是创建自己的类，该类派生自EventArgs：

    public class MyEventArgs : EventArgs
    {
        private readonly string _myFirstString;
        private readonly string _mySecondString;

        public MyEventArgs(string myFirstString, string mySecondString)
        {
            _myFirstString = myFirstString;
            _mySecondString = mySecondString;
        }

        public string MyFirstString
        {
            get { return _myFirstString; }
        }

        public string MySecondString
        {
            get { return _mySecondString; }
        }
    }

并像这样使用它：

public event EventHandler<MyEventArgs> MyEvent;

要举起活动，您可以这样做：

    protected virtual void OnMyEvent(string myFirstString, string mySecondString)
    {
        EventHandler<MyEventArgs> handler = MyEvent;
        if (handler != null)
            handler(this, new MyEventArgs(myFirstString, mySecondString));
    }

Answer 2

制作你的课程并为EventArgs扩展，并传递它

public class YourCustomeEvent : EventArgs
{
   public string yourVariable {get; }
}

现在你必须像这样提供你的自定义类

 public event EventHandler<YourCustomeEvent> MyEvent;

在eventArgs中发送两个字符串的语法

2 个答案: