如何在密钥以数字开头的地方输出此JSON值?

时间:2012-09-20 23:08:31

标签: php json

接受这个json回复:

    {
   "self":"http://macpro.local:2990/jira/rest/api/2/issue/CSS-4/votes",
   "votes":2,
   "hasVoted":true,
   "voters":[
      {
         "self":"http://macpro.local:2990/jira/rest/api/2/user?username=admin",
         "name":"admin",
         "avatarUrls":{
            "16x16":"http://macpro.local:2990/jira/secure/useravatar?size=small&avatarId=10062",
            "48x48":"http://macpro.local:2990/jira/secure/useravatar?avatarId=10062"
         },
         "displayName":"admin",
         "active":true
      },
      {
         "self":"http://macpro.local:2990/jira/rest/api/2/user?username=timn_1",
         "name":"timn_1",
         "avatarUrls":{
            "16x16":"http://macpro.local:2990/jira/secure/useravatar?size=small&avatarId=10062",
            "48x48":"http://macpro.local:2990/jira/secure/useravatar?avatarId=10062"
         },
         "displayName":"User Two",
         "active":true
      }
   ]
}

我对如何从上面获取avatarUrls-> 16x16感到茫然。我用以下命令很容易地得到其他所有东西:

$decoded = json_decode($result);
$decoded->votes; //returns # of votes
$decoded->voters->name; //returns the name

但是如何获得16x16的价值?如果我尝试这个,我会收到错误:

$decoded->voters->avatarUrls->16x16;

1 个答案:

答案 0 :(得分:4)

一如既往。

$decoded->voters->avatarUrls->{'16x16'}
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