在角色后从url获取一个字符串

Question

从这样的网址中仅获取 B005PB3YHU 部分的最佳方式是什么？ ： http://www.amazon.com/Designer-Bow-Ties-Y306/dp/B005PB3YHU%3FSubscriptionId%3DAKIAIM6KP3HMBKZXA2EA%26tag%3Dmenbowtie-20%26linkCode%3Dxm2%26camp%3D2025%26creative%3D165953%26creativeASIN%3DB005PB3YHU

Answer 1

使用parse_url和parse_string：
http://php.net/manual/en/function.parse-url.php
http://php.net/manual/en/function.parse-str.php

$query = parse_url($url,PHP_URL_QUERY);
parse_str($query,$parts);
echo $parts['creativeASIN'];

Answer 2

在@ jimp的答案的基础上，你需要首先urldecode将％##更改为PHP理解的东西：

$url = 'http://www.amazon.com/Designer-Bow-Ties-Y306/dp/B005PB3YHU%3FSubscriptionId%3DAKIAIM6KP3HMBKZXA2EA%26tag%3Dmenbowtie-20%26linkCode%3Dxm2%26camp%3D2025%26creative%3D165953%26creativeASIN%3DB005PB3YHU';
# urldecode will remove the %## encoding, and make the url look like:  
# http://www.amazon.com/Designer-Bow-Ties-Y306/dp/B005PB3YHU?SubscriptionId=AKIAIM6KP3HMBKZXA2EA&tag=menbowtie-20&linkCode=xm2&camp=2025&creative=165953&creativeASIN=B005PB3YHUB005PB3YHU
$query = parse_url(urldecode($url), PHP_URL_QUERY);
parse_str($query, $parts);
echo $parts['creativeASIN'];