查询连接三个表yii

Question

如何将mysql查询转换为yii。？

我有3张桌子

1. user_header
2. 客户
3. customer_ratings

这是我的SQL查询

SELECT t.email 
FROM   otz_user_header t 
       JOIN otz_customers r 
         ON t.user_id = r.customer_user_id 
       JOIN otz_customer_ratings cr 
         ON cr.customer_user_id = r.customer_user_id 
WHERE  r.rate_auto_approve = 0 
       AND r.rate_email_time IS NOT NULL 
       AND r.total_rating_count IS NOT NULL 
       AND cr.rating_date < Curdate() 
       AND cr.rating_date > Date_sub(Curdate(), INTERVAL 7 day) 

如何将此查询转换为yii？

提前致谢。

Answer 1

＆＃34;鼬＆＃34;回答是正确的，但如果你正在寻找积极的记录......

型号： UserHeader

关系：

'activeCustomers' => array(
     self::HAS_MANY, 
     'Customer', 
     'customer_user_id', 
     'condition' => 'activeCustomers.rate_auto_approve=0 
                  AND activeCustomers.rate_email_time IS NOT NULL 
                  AND activeCustomers.total_rating_count IS NOT NULL'
),

型号：客户

关系：

'lastWeekRatings' => array(
     self::HAS_MANY, 
     'CustomerRating', 
     'customer_user_id', 
     'condition' => 'lastWeekRatings.rating_date < CURDATE() 
        AND lastWeekRatings.rating_date > DATE_SUB( CURDATE(), INTERVAL 7 DAY )'
),

以下代码返回与查询相同的MODEL对象。 （我还没有测试过它）

$useremails = UserHeader::model()
     ->with('activeCustomers', 'activeCustomers.lastWeekRatings')
     ->findAll(array(
           'select' => 't.email'
      ));
print_r($useremails);

Answer 2

使用DAO（数据访问对象）

<强> MODEL

---

public function test(){
        $sql = "SELECT t.email
            FROM otz_user_header t
            JOIN otz_customers r ON t.user_id = r.customer_user_id
            JOIN otz_customer_ratings cr ON cr.customer_user_id = r.customer_user_id
            WHERE r.rate_auto_approve =0
            AND r.rate_email_time IS NOT NULL
            AND r.total_rating_count IS NOT NULL
            AND cr.rating_date < CURDATE( )
            AND cr.rating_date >DATE_SUB( CURDATE( ) , INTERVAL 7
            DAY )";

        return Yii::app()->db->createCommand($sql)->queryAll();
            }